Gamma rays are high-frequency EM waves and radio waves are low-frequency. Which characteristics are the same for both waves?

A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit

Aloiza [94]

Answer:

0.04328 H

0.00288 seconds

0.01326 seconds

Explanation:

V = Voltage = 6.3 V

R = Resistance = 15 Ω

L = Inductance

I = Decayed current = 0.21 A

t = Time to decay = 2 ms

Maximum Current is given by

$I_0=\frac{V}{R}\\\Rightarrow I_0=\frac{6.3}{15}\\\Rightarrow I_0=0.42\ A$

Current in the circuit is given by

$I=I_0exp\frac{-Rt}{L}\\\Rightarrow ln\frac{I_0}{I}=\frac{Rt}{L}\\\Rightarrow L=\frac{Rt}{ln\frac{I_0}{I}}\\\Rightarrow L=\frac{15\times 2\times 10^{-3}}{ln\frac{0.42}{0.21}}\\\Rightarrow L=0.04328\ H$

The inductance is 0.04328 H

Time constant is given by

$\tau=\frac{L}{R}\\\Rightarrow \tau=\frac{0.04328}{15}\\\Rightarrow \tau=0.00288\ s$

Time constant is 0.00288 seconds

Time required is given by

$t=\tau ln\frac{I_0}{I}\\\Rightarrow t=0.00288\times ln\frac{I_0}{0.01I_0}\\\Rightarrow t=0.01326\ s$

The time to reach 1% of its original value is 0.01326 seconds

7 0

4 years ago

which object has the most gravitational potential energy? A. an 8 kg book at a height of 3m B. an 5 kg book at a height of 3 m C

astra-53 [7]

I think A is the correct answer because its high is more higher compared to the others, and the mass really does not matter, to know the gravitational potential energy, we need to know how high the object is located because gravity does not show any favor to an object that has more mass or an object that doesnt

6 0

4 years ago

Read 2 more answers

What is the highest you can get before reaching space and start floating

grin007 [14]

327,360 feet
most aviation experts agree that the point where space begins is approximately 62 miles up. (62x5280=327,360).

6 0

3 years ago

3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P

KIM [24]

Answer:

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

$E=\frac{F}{Q}$

But the force F

$F= \frac{kQ1Q2}{r^2}$

But the electric field intensity due to a point charge Q at a distance r meters away is given by

$E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }$

<em>From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases</em>

6 0

3 years ago

How many neutrons is there in that element that has 36 protons and 36 electrons

bagirrra123 [75]

You need to know the mass number to work it out. I can see you have it but it's not visible on your photo.

Every proton weighs 1 and every neutron weighs 1 so if you know the total mass of the nucleus and the number of protons, then you can do:
Mass Number - Proton Number = Neutron Number
because the rest of the mass (that isn't from the protons) must come from the neutrons. Make sense?

3 0

3 years ago