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3 years ago

Discuss the relationship between electric and magnetic fields. How are they related?

1 answer:

4 0

Discuss the relationship between electric and magnetic fields. How are they related?

The magnetic field is related to the electric field in such a way that magnetic fields moves perpendicular the electric field. This relationship exists between a magnetic field and an electric field is a consequence of associating elementary particles.

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The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it i

andreyandreev [35.5K]

The apparent weight of a 1.1 g drop of water is 4.24084 N.

<h3>What is Apparent Weight?</h3>

According to physics, an object's perceived weight is a characteristic that describes how heavy it is. When the force of gravity acting on an object is not counterbalanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.
By definition, an object's weight is equal to the strength of the gravitational force pulling on it. It follows that even a "weightless" astronaut in low Earth orbit, with an apparent weight of zero, has almost the same weight that he would have if he were standing on the ground; this is because the gravitational pull of low Earth orbit and the ground are nearly equal.

Solution:

N = Speed of rotation = 1250 rpm

D = Diameter = 45 cm

r = Radius = 22.5 cm

M = Mass of drop = 1.1 g

Angular speed of the water = $\omega = \frac{2\pi N}{60}$

$\omega = \frac{2\pi \times 1250}{60}$

$\omega = 130.89 rad/s$

Apparent weight is given by

$W _a = M\omega^{2}R$

$W_a = 1.1 \times 10^-^3\times (130.89)^2\times 0.225$

$W_a$ = 4.24084 N

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Question:

The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1250 rpm around a vertical axis. What is the apparent weight of a 1.1 g drop of water?

7 0

1 year ago

Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

$\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}$

Where U is potential energy and K is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

$\displaystyle U_i = K_f$

Substitute and solve for final velocity:
$\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\ 2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ & =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}$

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

8 0

2 years ago

Which countries were considered the three major Axis Powers?

wariber [46]

The main Axis powers were Germany, Japan and Italy. The Axis leaders were Adolf Hitler (Germany), Benito Mussolini (Italy), and Emperor Hirohito (Japan)

4 0

2 years ago

How does the number of moles of solute before a dilution compare with the number of moles of solute after the dilution?

USPshnik [31]

The quantity of moles of a solute won't change as an answer is weakened, be that as it may, the centralization of the solute will diminish. If you somehow happened to dissipate the water from the weakened arrangement, you would have an indistinguishable number of moles of solute from when you began. You can test this by looking at the mass of the solute before creating the answer for the mass of the solute after the arrangement was weakened. The two masses ought to be the same.

5 0

2 years ago

When we look into the night sky, we notice that there are stars dotted across the landscape. We also notice that there are regio

IRISSAK [1]

Answer: these regions of darkness are due to no stars being in these regions of the night sky

5 0

3 years ago