Question

The length of a rectangle is represented by 4a+3b and its width is represented by 3a-2b. Write the polynomical for the perimeter of the rectangle.

Answer 1

Answer:

$P=(14a+2b)$

Step-by-step explanation:

we know that

The perimeter of a rectangle is equal to

$P=2(L+W)$

where

L is the length

W is the width

we have

$L=(4a+3b)\ units\\W=(3a-2b)\ units$

substitute

$P=2[(4a+3b)+(3a-2b)]$

Combine like terms

$P=2(7a+b)$

Apply distributive property

$P=(14a+2b)\ units$