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Answer:
36.0 kpsi2.
Explanation:
From the question
Sut=110 kpsi
Se’=0.5(110)=55 kpsi
For surface factor ka,
a=2.70, b= -0.265, ka=a(Sut)b=2.70(110)-0.265=0.777
Assuming the worst case for size factor kb, and since 0.11 less than or equal to d less than or equal to 2in,
Therefore:
kb=0.879d-0.107 = 0.879(1.5)-0.107=0.842
Hence, the endurance strength is Se= ka kb Se’ = 36.0 kpsi2.
Answer:
film critic
Explanation:
they are referred as film critic
hope this helps
Answer:
10.007
Explanation:
Assuming we have to find out the compression ratio of the engine
Given information
Cubic capacity of the engine, V = 245 cc
Clearance volume, V_c = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
Volume of the engine V =
plugging values we get
245 =
Solving we get D =7 cm
therefore, L= 7/1.1 =6.36 cm
Now,
the compression ratio is given as:
r =(V+V_c)/V_c
on substituting the values, we get
r = (245+27.2)/27.2 =10.007
Hence, Compression ratio = 10.007