Answer:
The question is a problem that requires the principles of fracture mechanics.
and we will need this equation below to get the Max. Stress that exist at the tip of an internal crack.
Explanation:
Max Stress, σ = 2σ₀√(α/ρ)
where,
σ₀ = Tensile stress = 190MPa = 1.9x10⁸Pa
α = Length of the cracked surface = (4.5x10⁻²mm)/2 = 2.25x10⁻⁵m
ρ = Radius of curvature of the cracked surface = 5x10⁻⁴mm = 5x10⁻⁷m
Max Stress, σ = 2 x 1.9x10⁸ x (2.25x10⁻⁵/5x10⁻⁷)⁰°⁵
Max Stress, σ = 2 x 1.9x10⁸ x 6.708 Pa
Max Stress, σ = 2549MPa
Hence, the magnitude of the maximum stress that exists at the tip of an internal crack = 2549MPa
Answer:
Explanation:
it is given that diameter = 8.6 cm
current =2.7 ampere
number of turns = 15
magnetic field =0.56 T
maximum torque= BINASINΘ for maximum torque sinΘ=1
so maximum torque==0.56×2.7×0.005806×15=0.13174 Nm
Crystalline silicon
hope this helps!! <3
Answer:
Explanation:
A continuous fiber-reinforced composite is to be produced by dispersing 60 vol% carbon fibers in a polycarbonate matrix. if the stress in the polycarbonate matrix when the carbon fibers fail is 45 mpa, the longitudinal elastic modulus of the composite using rule of mixture
Use SAS(Side angle side ) rule.
Then cosine law i.e a^2=b^2+c^2-2*b*c*COSA
We will get a=69 mm
Now we have all sides use sine law
a/sinA=b/sinB
We will get B=60(deg)
And use the law: sum of all angles of triangle is 180(deg)
We will get C=75(deg).