Question

Find the area of the kite. The figure is not drawn to scale.

Answer 1

Answer:

The area of the kite is $42\ units^{2}$

Step-by-step explanation:

we know that

The area of a kite is half the product of the diagonals

so

$A=\frac{1}{2}(D1*D2)$

we have

$D1=2*(3)=6\ units$

Find the length side of diagonal D2

Applying the Pythagoras Theorem

$D2=\sqrt{5^{2}-3^{2}} +10\\ \\D2=4+10\\ \\D2=14\ units$

Find the area of the kite

we have

$D1=6\ units$

$D2=14\ units$

substitute

$A=\frac{1}{2}(D1*D2)$

$A=\frac{1}{2}(6*14)=42\ units^{2}$