<h3><u>Answer;</u></h3>
A substance that is magnetic is a substance that can generate or produce magnetic field
<h3><u>Explanation;</u></h3>
- Magnetic substances generate magnetic field since they have atoms or molecules that have unpaired electrons.
- Magnetic materials may be either paramagnetic or ferromagnetic. Paramagnetic materials are materials such as aluminium in which become magnetized in a magnetic field but their magnetism disappears upon the removal of magnetic field.
- Ferromagnetic materials are materials such as nickel and iron which can reatin their magnetic properties even when magnetic field is removed.
Answer:
d.
50 m
Explanation:
v² = u² + 2as
s = (v² - u²) / 2a
s =(25² - 0²) / (2(6.25))
s = 50 m
The 4 signifies the
atomic weight, and the 2 subscribes the element's
atomic number(aka the number of protons in the atom).
Answer:
Explanation:
a ) Velocity vs time graph will be a straight line with negative slope , making a slope of 2 because slope of v-t graph gives the value of acceleration.
b ) v = 0 , u = 28 m/s
t = ?
v = u - at
0 = 28 - 2 t
t = 14 s
shuttle velocity will become zero after 14 sec.
c ) v ² = u² - 2 a s
0 = 28² - 2 x 2 x s
s = 28² / 4
= 196 m .
Complete question is;
a. Two equal sized and shaped spheres are dropped from a tall building. Sphere 1 is hollow and has a mass of 1.0 kg. Sphere 2 is filled with lead and has a mass of 9.0 kg. If the terminal speed of Sphere 1 is 6.0 m/s, the terminal speed of Sphere 2 will be?
b. The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1. The masses remain 1.0 kg and 9.0 kg, The terminal speed (in m/s) of Sphere 2 will now be
Answer:
A) V_t = 18 m/s
B) V_t = 10.39 m/s
Explanation:
Formula for terminal speed is given by;
V_t = √(2mg/(DρA))
Where;
m is mass
g is acceleration due to gravity
D is drag coefficient
ρ is density
A is Area of object
A) Now, for sphere 1,we have;
m = 1 kg
V_t = 6 m/s
g = 9.81 m/s²
Now, making D the subject, we have;
D = 2mg/((V_t)²ρA))
D = (2 × 1 × 9.81)/(6² × ρA)
D = 0.545/(ρA)
For sphere 2, we have mass = 9 kg
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρA))]
V_t = 18 m/s
B) We are told that The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1.
Thus;
Area of sphere 2 = 3A
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρ × 3A))]
V_t = 10.39 m/s