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Xelga [282]
3 years ago
12

Light travels 300,000,000m/sec, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in

one year. Based on this data: a. state the speed in m/sec using scientific notation b. state the speed in km/sec using scientific notation c. state the number of seconds in one year using scientific notation d. calculate the distance in meters of one light year e. state this distance in centimeters
Physics
1 answer:
dem82 [27]3 years ago
3 0
A) 3 x 10 ^ 8
b) 3 x 10 ^ 5
c) 3.2 x 10 ^ 7
d) 9.6 x 10 ^ 15 m
e) 9.6 x 10 ^ 17 cm
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The area of the united states that has the highest level of average daily solar radiation by month would be
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Decide which of the following day-to-day activities might be considered aerobic exercise?
erastova [34]

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The four-wheel-drive all-terrain vehicle has a mass of 385 kg with center of mass G2. The driver has a mass of 75 kg with center
jenyasd209 [6]

The coefficient of friction is missing and it has a value of μ = 0.4

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a = 3.924 m/s²

Explanation:

I've attached the kinematic free body diagram.

Taking the sum of all upward and downward forces,

EFy = 0;

N1 + N2 - m_p•g - m_v•g = 0

N1 + N2 = m_p•g + m_v•g

Where;

N1 and N2 are the normal reactions at the wheels

m_p is the mass of the driver

m_v is the mass of the vehicle

g is the acceleration due to gravity.

Plugging in the relevant values in the question,we obtain;

N1 + N2 = (385 + 75) x 9.81

N1 + N2 = 4512.6N - - - (eq1)

Now, taking sum of all horizontal forces;

EFx = (m_p + m_v) x a

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μ(N1 + N2) = (mp + mv) x a

Thus,

0.4(N1 + N2) = (385 + 75)a

0.4(N1 + N2) = 460a

N1 + N2 = 1150a

From eq(1),N1 + N2 = 4512.6N

Thus,

1150a = 4512.6N

a = 4512.6/1150

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Therefore, the acceleration, a = 3.924 m/s²

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3 years ago
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Tamiku [17]

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