The rate of cooling determines ....... and ......

Cody lives in Florida along the eastern coast. The kind of air mass likely to occur

Svetllana [295]

The air is likely to be humid because it is coastal and very warm there

5 0

3 years ago

Problem 7.46 - enhanced - with feedback a 200 g , 25-cm-diameter plastic disk is spun on an axle through its center by an electr

vladimir1956 [14]

<span>Torque = I * Î± I = Â˝ * m * r^2 = Â˝ * 0.2 * 0.125^2 = 0.0015625 As the disk rotates one time, it rotates an angle of 2 Ď€ radians. Total angle = 1600 * 2 Ď€ = 3200 * Ď€ One minute is 60 seconds. To determine its initial angular velocity, divide this angle by 60. Ď‰ = 53â…“ * Ď€ This is approximately 167.55 rad/s. To determine the angular acceleration, divide by 4.1 seconds. Î± = 53â…“ * Ď€ Ă· 4.1 This is approximately 4.09 rad/s^2 Torque = 0.0015625 * (53â…“ * Ď€ Ă· 4.1) This is approximately 0.0639 N * m. electron1 Â· 2 years ago</span>

8 0

4 years ago

Newton’s second law relates an object’s acceleration to its mass and the net force acting on it. Does newton’s second law apply

alexgriva [62]

No, newton’s second law does not apply to a situation in which there is no net force.

<h3>What is force?</h3>

A force is a push or pull upon an object which stops or tends to stop the object and move or tends to move an object.

No, newton’s second law apply to a situation in which there is no net force because force compels the object to move in the direction in which force is applied so we can conclude that force is compulsory to move an object.

Learn more about force here: brainly.com/question/12970081

3 0

3 years ago

Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitu

ANEK [815]

Answer:

The electric field will be decreased by 29%

Explanation:

The distance between point P from the distance z = 2.0 R

Inner radius = R/2

Outer raidus = R

Thus;

The electrical field due to disk is:

$\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)$ )

$\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)$

Similarly;

$\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)$

However; the relative difference is: $\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}$