Given:
In triangle ABC, AB = AC, AD is angle bisector and measure of angle C is 49 degrees.
To find:
The value of x and y.
Solution:
In triangle ABC,
(Given)
So, triangle ABC is an isosceles triangle and by the definition of base angles the base angles of isosceles triangle are congruent.
In isosceles triangle ABC,
The angle bisector of an isosceles triangle is the median and altitude of the triangle. So, the angle bisector is perpendicular to the base.
In triangle ABD,
[Angle sum property]
Therefore, the correct option is B.
64 as it’s multiplied by 2 each time
Answer:
C. (-2,4)
Step-by-step explanation:
We have been given a function 
and we are asked to find the vertex of our absolute value function.
The rules for the translation of a function are as follows:
Upon comparing our absolute function with above transformations we can see that our function is shifted to two units right of the origin(0,0) so x coordinate of our absolute function will be -2.
Our function is shifted upward from origin by 4 units, therefore, y-coordinate of our absolute value function will be 4.
Therefore, the vertex of our absolute value function will be on point (-2,4) and option C is the correct choice.
Start circle: πd = (3.14)(19) = 59.7
Move diagonally to the circle with the radius of 6.2.
Second circle: 2πr = 2(3.14)(6.2) = 39
Move upwards to the circle with the radius of 10.5
third circle: 2πr = 2(3.14)(10.5) = 66
Move right to the circle with the diameter of 16.6
Fourth circle: πd = (3.14)(16.6) = 52.2
Move down to the circle with the diameter of 7.7
fifth circle: πd = (3.14)(7.7) = 24.2
Move down to the circle with the diameter of 50
Sixth circle: πd = (3.14)(50) = 157.1
Move left to the circle with the radius of 11.8
Seventh circle: 2πr = 2(3.14)(11.8) = 74.1
Move down to the circle with the radius of 38
Eight circle: 2πr = 2(3.14)(38) = 238.8
Move right to the circle with the diameter of 1.1
ninth circle: πd = (3.14)(1.1) = 3.5
Move right to the circle with the radius of 14.8
10th circle = 2πr = 2(3.14)(14.8) = 93
Move up to the end.
Hope this helps :)
The external tangent is line s
