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JulijaS [17]
3 years ago
9

The purpose of teaching high levels of math is to filter out students who lack logical intelligence

Physics
1 answer:
Pachacha [2.7K]3 years ago
7 0
Answer: False I think that is worded weird tho
You might be interested in
You drive a car for 2.0 h at 60 km/h, then for another 3.0 h at 85 km/h. What is your average velocity
Anon25 [30]

Answer:

Explanation:

Average velocity is found in the total displacement experienced in the trip divided by the total time it took to make this trip. If, for the first 2.0 hours, the car travels at 60 km/hr, then in 2.0 hours the car can travel 120 km; if it then travels for 3.0 at 85 km/hr, it can travel 255 km in the same direction. The total time this took was 5.0 hours. So doing the math and rounding correctly by following the rules for the adding and subtracting of sig fig's:

v=\frac{120+255}{5.0}=\frac{380}{5.0}=76\frac{km}{hr}

If you do not round when you add, the average velocity is 75 km/hr

8 0
3 years ago
Which nucleus complete the following equation
rosijanka [135]

(C) ^{208}_{84}\text{Po}

Explanation:

^{212}_{86}\text{Rn} \rightarrow \:^4_2\text{He} + \:^{208}_{84}\text{Po}

7 0
3 years ago
What is the friction​
Mnenie [13.5K]

Explanation:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in

3 0
3 years ago
A ladder of length 10 is leaning against a wall. The vertical wall is frictionless while the horizontal surface is rough. The an
bogdanovich [222]

Answer:

105.1N

Explanation:

According to the newton second law

\sum F_x = ma_x\\F_m - F_f = ma_x\\

Since the acceleration is zero, then;

F_m - F_f = 0\\Fm = F_f\\

Since;

F_m = mg sin \theta, \  hence \ F_f = mg sin \theta

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

8 0
3 years ago
You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change
Sophie [7]
The change in potential energy of an object is given by
U=mg \Delta h
where
m is the mass of the object
g is the gravitational acceleration
\delta h is the increase in altitude of the object

In our problem, m=2.5 kg is the mass of the book, g=9.81 m/s^2 and 
\Delta h=2.6 m -1.2 m=1.4 m is the increase in altitude of the book, so its variation of potential energy is
U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J
8 0
4 years ago
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