An someone help me on the bottom part

Mathematics

1 answer:

maw [93]3 years ago

8 0

=,>,<,<,= convert them each to where they match in their units

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Find (if possible) the complement and the supplement of each angle. (if not possible, enter impossible.) (a) π 10 complement rad

blagie [28]

In this question, we have to find the complement and supplement of the given angles .

Complementary angles are those angles whose sum is 90 degree and supplementary angles are those angles whose sum is 180 degree.

So to find the complement and supplement angles, we need to subtract the given angles from pi/2 and pi respectively .

$\frac{ \pi}{10}
\\
complement \ angle = \frac{ \pi}{2} - \frac{ \pi}{10} \\ = \frac{4 \pi}{10} = \frac{ 2 \pi}{5}
\\
Supplement \ angle = \pi - \frac{ \pi}{10} = \frac{9 \pi}{10}$

$\frac{9 \pi}{10}
\\
Complement \ angle = \frac{ \pi}{2} - \frac{9 \pi}{10} = \frac{-4 \pi}{10} = -\frac{2 \pi}{5}
\\
Supplement \ angle = \pi - \frac{9 \pi}{10} = \frac{ \pi}{10}$

4 0

3 years ago

Graph y = f(x) = 3(2)x. Adjust the equation to make the y-intercept (0, −3). Which response is not correct?

Sauron [17]

Answer:

Replace x with −x.

f(x) = 3(2)−x is not correct because the y-intercept is (0, 3).

the answer is B

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered

Karolina [17]

By Green's theorem, the integral of $\vec F$ along $C$ is

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy$

which is 6 times the area of $D$ , the region with $C$ as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle $\theta$ and radius $r$ , the area $A$ of the sector is proportional to the circle's overall area according to