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3241004551 [841]
3 years ago
6

Find three consecutive integers whose sum is 63

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0
What three consecutive integers have a sum of 63? Which means that the first number is 20, the second number is 20 + 1 and the third number is 20 + 2. Therefore, three consecutive integers that add up to 63 are 20, 21, and 22.
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What am i supposed to do??
miskamm [114]
Exterior angle theorem
16x - 7 = 8x + 2 + 10x - 19    ===>  16x -7 = 18x - 17
16x - 16x - 7 = 18x - 16x - 17 ===> -7 = 2x - 17
-7 + 17 = 2x - 17 + 17             ===> 10 = 2x ======> 5 = x
Plug x in to each equation.
Angle P: 8(5) + 2 = 42 deg, Angle Q: 10(5) - 19 = 31
The sum of interior angles = 180. 180 - 42 -31 = 107 deg (angle of PRQ)
To check that line other angle : 16(5) -7 = 73 deg + 107 = 180 deg


5 0
3 years ago
(7x-y=7<br>(x+2y=6 estimate the solution to the system of equations ​
jolli1 [7]

Multiply the first equation by 2 to then use elimination by adding the 2 equations.

So, 14x-2y=14

+. x+2y=6

Equals 15x=20 so x=20/15=4/3

Plug in to first equation to get y

7(4/3)-y=7

28/3-y=7

28/3-y=21/3

So y=7/3

Plug both x and y into second equation to check

4/3+2(7/3)=

4/3+14/3=18/3=6 it works

So x=4/3, y=7/3

Hope this helps! Have a blessed day!

8 0
4 years ago
4/7 - -3/5 step by step pls explain​
lidiya [134]

Answer:

41/35

Step-by-step explanation:

Simplify the following:

4/7 + 3/5

Put 4/7 + 3/5 over the common denominator 35. 4/7 + 3/5 = (5×4)/35 + (7×3)/35:

(5×4)/35 + (7×3)/35

5×4 = 20:

20/35 + (7×3)/35

7×3 = 21:

20/35 + 21/35

20/35 + 21/35 = (20 + 21)/35:

(20 + 21)/35

| 2 | 1

+ | 2 | 0

| 4 | 1:

Answer: 41/35

5 0
4 years ago
Help me there is brainliest insured
Ronch [10]

Answer:

33

Step-by-step explanation:

44 - 25% off is 33

3 0
3 years ago
Read 2 more answers
Help again? I still don’t understand and I have two wrong
GarryVolchara [31]
The equation is y=1/2x+2
hope this helps
3 0
3 years ago
Read 2 more answers
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