N= -16.5
Subtract 33 then divide by 2
2n=-33
n=-33/2 or n=-16.5
Answer:

Step-by-step explanation:
Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61
To list: numbers from least to greatest
Solution:
Let the three consecutive odd integers be
.
According to question,

So, the integers are 
Numbers from least to the greatest: 
Answer:

Step-by-step explanation:
Given the expression 
According to the law of logarithm;
loga + log b = log(ab) and log a - log b = log(a/b)
The given expression becomes;

P(r/w) is the probability of picking a red rose at first picking and a white rose at second picking.
P(w/r) is the probability of picking a white rose at first picking and a red rose at second picking.
P(r/w) =

×

=

P(w/r) =

×

=

Notice that the second fraction is out of 18 because the second picking of rose will be out of 18 since the first rose is not replaced.
P(r/w) equals to P(w/r)