<img src="https://tex.z-dn.net/?f=5%3D%20x%5E%7B2%7D%20%2B2x" id="TexFormula1" title="5= x^{2} +2x" alt="5= x^{2} +2x" align="ab

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creativ13 [48]

2 years ago

smiddle" class="latex-formula">
solve the equation using any method you prefer. Give imaginary roots.

Mathematics

1 answer:

Mrrafil [7]2 years ago

3 0

$5=x^2+2x\\
x^2+2x-5=0\\
x^2+2x+1-6=0\\
(x+1)^2=6\\
x+1=\sqrt6 \vee x+1=-\sqrt6\\
x=-1+\sqrt6 \vee x=-1-\sqrt6$

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Related link:

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Answer:

See Explanation

Step-by-step explanation:

Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified

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