<img src="https://tex.z-dn.net/?f=5%3D%20x%5E%7B2%7D%20%2B2x" id="TexFormula1" title="5= x^{2} +2x" alt="5= x^{2} +2x" align="ab

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creativ13 [48]

3 years ago

smiddle" class="latex-formula">
solve the equation using any method you prefer. Give imaginary roots.

Mathematics

1 answer:

Mrrafil [7]3 years ago

3 0

$5=x^2+2x\\
x^2+2x-5=0\\
x^2+2x+1-6=0\\
(x+1)^2=6\\
x+1=\sqrt6 \vee x+1=-\sqrt6\\
x=-1+\sqrt6 \vee x=-1-\sqrt6$

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Step-by-step explanation:

* Lets explain how to solve the problem

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and $(x_{2},y_{2})$ i s $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

- So at first we will find the distance between the three points

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- By using the rule of distance

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∴ The distance between branches A and B = 6.325 miles

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∴ The distance between branches B and C = 4 miles

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∴ The distance between branches A and C = 6.325 miles

- A bank employee drives from Branch A to Branch B and then

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∴ The distance the employee may have driven before getting

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∴ The minimum total distance the employee may have driven

before getting stuck in traffic is 8.3 miles

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