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creativ13 [48]
3 years ago
13

smiddle" class="latex-formula">
solve the equation using any method you prefer. Give imaginary roots.
Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0
5=x^2+2x\\
x^2+2x-5=0\\
x^2+2x+1-6=0\\
(x+1)^2=6\\
x+1=\sqrt6 \vee x+1=-\sqrt6\\
x=-1+\sqrt6 \vee x=-1-\sqrt6
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