If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l
now
solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum
notice the
so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0
so.. check the critical points on the other
Answer:
1759.52cm^3
Step-by-step explanation:
Given data
Cylinder E
h = 30 cm and
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*30
V= 3.142*16*30
V=1508.16 cm^3
Cylinder F
h=5 cm
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*5
V= 3.142*16*5
V=251.36 cm^3
Hence the total volume is
=251.36+1508.16
= 1759.52cm^3
29,028ft 5 and 1/2 miles About as big as 20 empire state buildings.
<u>Answer:</u>
5x = 100°
4x = 80°
<u>Step-by-step explanation:</u>
We are given a diagram with a straight line AC being intersected by another line BD and we are to find the two mentioned angles.
We know that the two angles (5x° and 4x°) are supplementary so their sum would be equal to 180°.
So we can write it as:
Finding the measure of both the angles:
100°
80°
Answer:
y = 0.64/x^3
Step-by-step explanation:
If y is inversely proportional to a^3, we can write the equation:
y * a^3 = k
Using a = 2 and y = 10, we have:
10 * 2^3 = k
k = 80
If a is directly proportional to x, we can write the equation:
a = c * x
Using x = 4 and a = 20, we have:
20 = c * 4
c = 5
Now, using the value of a = 5*x in the equation y * a^3 = 80, we have:
y * (5x)^3 = 80
y * 125x3 = 80
y = 80/(125x3) = 0.64/x^3
