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3 years ago

Which graphs are proportional?

Mathematics

2 answers:

yuradex [85]3 years ago

8 0

All of them except for #6 and #9 =>

Kaylis [27]3 years ago

5 0

Answer:

3,4,5,6,9

Step-by-step explanation:

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G is a trigonometric function of the form g(x)=a sin (bx+c)+d.

emmainna [20.7K]

Answer:

Formula for g(x) is $g(x) = 3 sin(\frac{\pi }{5}x + \frac{\pi }{5} ) + 6$

Step-by-step explanation:

Given - g is a trigonometric function of the form g(x)=a sin (bx+c)+d. The function intersects its midline at (-1 , 6) and has a minimum point at (-3.5 , 3)

To find - Find a formula for g (x). Give an exact expression.

Proof -

Given that,

g(x)=a sin (bx+c)+d

We know that, Midline is present in between maximum and minimum

Here given that, minimum is present is 3 and midline is present at 6

So, Maximum occurs at 9.

Now,

We know that,

Standard form of sine function is - g(x) = Asin(B(x-C)) + D

Where

A = Amplitude

and Amplitude = (Maximum - minimum) / 2

= (9 - 3)/ 2

= 6/2 = 3

⇒A = 3

Now,

Period = $\frac{2\pi }{B}$

⇒B = (2π) / Period

= (2π) / 10

= π/5

⇒B = π/5

Now,

Phase Shift : C = -1 ( i.e. 1 to the left)

Vertical Shift : D = 6

So,

We get

g(x) = Asin(B(x-C)) + D

= $3 sin(\frac{\pi }{5}(x -(- 1))) + 6$

⇒ $g(x) = 3 sin(\frac{\pi }{5}x + \frac{\pi }{5} ) + 6$

∴ we get

Formula for g(x) is $g(x) = 3 sin(\frac{\pi }{5}x + \frac{\pi }{5} ) + 6$

8 0

3 years ago

Divide.<br> (8x^3+ 31x^2+ 6x +40) + (2x+8)

aksik [14]

Answer:

divide them by what?

or fivide it with eachother?

7 0

3 years ago

Jess is painting his car. He's created a purple color that uses red paint and blue paint in a ratio of 6:5. Jess uses 15

lilavasa [31]

B
I’m sure It’s current answer

4 0

4 years ago

Read 2 more answers

To receive a driver license, sixteen year-olds at Culliver High School have to pass both a written and a practical driving test.

Lesechka [4]

Answer:

Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Step-by-step explanation:

Consider the provided information.

Sixteen year-olds at Culliver High School have to pass both a written and a practical driving test.

Everyone has to take the tests, and no one failed both tests.

30% of the 16 year-olds who passed the written test did not pass the practical,

Statement 1: There are 188 sixteen year-olds at Culliver High School.

That means 30% of 188 passed in written test.

Or 70% of 188 sixteen year old passed in one or both test.

But we need to find the number of sixteen year-olds at Culliver High School received their driver license?

Which is not possible,

Thus, the statement is insufficient.

Statement 2: 20% of the sixteen year-olds who passed the practical test failed the written test.

That means 20% passed in practical test only and we know that 30% of sixteen year-olds passed in written test.

Therefore, 50% of total passed in both.

But this tells us the percentage of student passed in both and we wants a definite number,

Thus, the statement is not sufficient alone.

Therefore, Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

6 0

4 years ago

Jen's teacher has 64 silly bands to give to 16 students. How many silly bands can each student have?

Yanka [14]

divide 64 by 16

$\frac{64}{16}$ = 4

7 0

4 years ago