Step-by-step explanation:
You want the to find the value of k such that the y coordinate of the vertex is 0.
0=x2−6x+k
The x coordinate, h, of the vertex is found, using the following equation:
h=−b2a
h=−−62(1)=3
Evaluate at x = 3:
0=32−6(3)+k
k=9
Answer:
True.
Step-by-step explanation:
A variable term is a term with a variable. 5y is your only variable term; therefore, it only has one variable term.
Log[6] * 4x2 + -1log[6] * x = 2
Reorder the terms for easier multiplication:
6 * 4glo * x2 + -1log[6] * x = 2
Multiply 6 * 4
24glo * x2 + -1log[6] * x = 2
Multiply glo * x2
24glox2 + -1log[6] * x = 2
Reorder the terms for easier multiplication:
24glox2 + -1 * 6glo * x = 2
Multiply -1 * 6
24glox2 + -6glo * x = 2
Multiply glo * x
24glox2 + -6glox = 2
Reorder the terms:
-6glox + 24glox2 = 2
Solving
-6glox + 24glox2 = 2
Solving for variable 'g'.
Move all terms containing g to the left, all other terms to the right.
Reorder the terms:
-2 + -6glox + 24glox2 = 2 + -2
Combine like terms: 2 + -2 = 0
-2 + -6glox + 24glox2 = 0
Factor out the Greatest Common Factor (GCF), '2'.
2(-1 + -3glox + 12glox2) = 0
Ignore the factor 2.
Subproblem 1
Set the factor '(-1 + -3glox + 12glox2)' equal to zero and attempt to solve:
Simplifying
-1 + -3glox + 12glox2 = 0
Solving
-1 + -3glox + 12glox2 = 0
Move all terms containing g to the left, all other terms to the right.
Add '1' to each side of the equation.
-1 + -3glox + 1 + 12glox2 = 0 + 1
Reorder the terms:
-1 + 1 + -3glox + 12glox2 = 0 + 1
Combine like terms: -1 + 1 = 0
0 + -3glox + 12glox2 = 0 + 1
-3glox + 12glox2 = 0 + 1
Combine like terms: 0 + 1 = 1
-3glox + 12glox2 = 1
Solve for w.
2=2(lw+lh+wh)
Flip the equation.
2hl+2hw+2lw=2
Add -2hl to both sides.
2hl+2hw+2lw+−2hl=2+−2hl
2hw+2lw=−2hl+2
Factor out variable w.
w(2h+2l)=−2hl+2
Divide both sides by 2h+2l.
w(2h+2l) / 2h+2l=−2hl+2 / 2h+2l
w=−hl+1/h+l
, while the range is ![(0,4]](https://tex.z-dn.net/?f=%280%2C4%5D)
.