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Oksi-84 [34.3K]
2 years ago
8

First person to answer this question get 11 points!

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
3 0
Polygon means many sided

quadrilateral means 4 sides
parellelogram means 2 pairs of parrelel sides
rectangle=parellelogram with 4 right angles


so thea snwer is A,B,C or all of them

if you need to pick one only, I would pick B because it has the name RECTANGLE specifically stated so the answer is ABC or if you must pick one then the naswer is B
You might be interested in
We know that February has either 28 or 29 days, but there is a year in the future, February will have 30 days
Karo-lina-s [1.5K]

Answer:

The year 2020 is a leap year, which means February will have 29 days rather than 28, and the overall number of days will be 366 rather than 365. This was also the case in 2016, and the year 2024 will be a leap year once more.

Step-by-step explanation:

5 0
3 years ago
What is the value of this expression?<br> 5x (8 – 3) + 2
ivolga24 [154]

Answer:

27

Step-by-step explanation:

5 x (8 - 3) +2

5 x (5) + 2

25 + 2

27

Hope that helps!

4 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (4,1) and (8,-3)?
Rus_ich [418]

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

  so (-3-1)/(8-4)

  -4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so    1=-1(4)+b

        1=-4+b

        1+4=b

so b= 5

therefore the equation is  y=-x+5   so d

8 0
3 years ago
Please help me with this please 2
kondaur [170]
Put this into a scientific calculator
1/3 x pi x 18 squared x 16
8 0
3 years ago
Match the equations with their solutions over the interval [0, 2π].
nignag [31]

I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs are:

cos(x)tan(x) – ½ = 0 → π/6 and 5π/6

cos(π/6)tan(π/6) – ½ = 0

cos(5π/6)tan(5π/6) – ½ = 0

 

sec(x)cot(x) + 2 = 0 → 7π/6 and 11π/6

sec(7π/6)cot(7π/6) + 2 = 0

sec(11π/6)cot(11π/6) + 2 = 0

 

sin(x)cot(x) + 1/sqrt2 = 0 → 3π/4 and 5π/4

sin(3π/4)cot(3π/4) + 1/sqrt2 = 0

sin(5π/4)cot(5π/4) + 1/sqrt2 = 0

 

csc(x)tan(x) – 2 = 0 → π/3 and 5π/3

csc(π/3)tan(π/3) – 2 = 0

csc(5π/3)tan(5π/3) – 2 = 0

5 0
3 years ago
Read 2 more answers
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