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3 years ago

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Adult humans have approximately 2.6x10^13 red blood cells and 3.92x 10^10 white blood cells. How many times greater is the numbe

r of red blood cells than the white blood cells

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer: The number of red blood cells is approximately 660 times greater than white blood cells.

Step-by-step explanation: In adult humans the blood has about 4,5 to 6 million red blood cells per cubic millimeter (mm3), while the normal value of white blood cells is between 5,000 and 10,000 per mm3.

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Find the area of the shaded region. Round your answer to the nearest hundredth.

valina [46]

Answer:

FIRSTLY GET THE AREA OF THE WHOLE CIRCLE BY USING FORMULA
$pi \times r ^2$
THEN AFTER THAT DIVIDE THE AREA BY 2
AFTER THAT UR ANSWER WILL COME

<em>PLEASE</em><em> </em><em>MARK ME AS BRAINLIEST</em><em> </em>

3 0

2 years ago

Read 2 more answers

1 1/5 is 6% of what number?

Ksenya-84 [330]

Answer:

36.67

Step-by-step explanation:

11/5=2.2

let the unknown no be x

6% of x=2.2

6/100 * x = 2.2

6x = 2.2*100

x = 220/6

x= 36.67

7 0

3 years ago

Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"

Levart [38]

Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

$3(-1)^4 = 3$

<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em> $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like $-1^4$ . However, since we're substituting in -1, it looks like $(-1)^4$ , so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in $-1\cdot-1\cdot-1\cdot-1=1$ .

Applying this logic to our original term, $3(-1)^4$ :

$3(-1\cdot-1\cdot-1\cdot-1)$
$3(1)$
$3$

Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: $-5x^2$

$-5(-1)^2$

Applying the same logic from our first term:

$-5(-1 \cdot -1)$
$-5(1)$
$-5$

Third term: $2x$

$2(-1) = -2$

-3 is just -3, no influence of x.

Combining our terms, we have $3-5-2-3$ .

This comes out to be -7, hence, the value of $f(-1)$ for our function $f(x)=3x^4-5x^2+2x-3$ is <u>-7</u>.

Hope this helped!

4 0

3 years ago

Read 2 more answers

In a batch of 960 calculators, 8 were found to be defective. What is a probability that a calculator chosen at random will be de

DaniilM [7]

Out of 960 calculators, 8 were found be to defective

Probability:
$\frac{8}{960}$
0.00833...
As a Percent:
0.00833....× 100
0.833%
To the nearest tenth of percentage:
0.833% ≈ 0.8%

8 0

3 years ago

Read 2 more answers

How do I confirm that f and g are inverses?

Anestetic [448]

Answer:

see explanation

Step-by-step explanation:

To show f and g are inverses we require to show that

f(g(x)) = x and g(f(x)) = x

f(g(x))

= f(6x - 4)

= $\frac{6x-4+4}{6}$ = $\frac{6x}{6}$ = x

-----------------------------------------------------------------------------

g(f(x))

= g( $\frac{x+4}{6}$ )

= ( 6 × $\frac{x+4}{6}$ ) - 4

= x + 4 - 4 = x

-------------------------------------------------

Hence f and g are inverses

4 0

3 years ago