Answer: y = 5x − 11
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
The line passes through (3,4) and (2, -1),
y2 = - 1
y1 = 4
x2 = 2
x1 = 3
Slope,m = (- 1 - 4)/(2 - 3) = - 5/- 1 = 5
To determine the y intercept, we would substitute x = 3, y = 4 and m= 5 into
y = mx + c. It becomes
4 = 5 × 3 + c
4 = 15 + c
c = 4 - 15 = - 11
The equation becomes
y = 5x - 11
If xy=0 we assume x and y equal 0
so
the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that
0=2x-5
5=2x
5/2=x
0=5x+4
-4=5x
-4/5=x
zeroes at x=5/2 and -4/5
For a rational number to have a terminating decimal expansion
q should be in the form 5^m and 2^n or both. If q is not in the form of either then it is a non terminating recurring decimal expansion
Hello from MrBillDoesMath!
Answer:
sin(A) = k/c
sin(C) = k/a
Discussion:
By definition of sine
,
sin(A) = side opposite angle / hypotenuse = k/c
sin(C) = side opposite angle/ hypotenuse = k/a
Added remark:
From the first equation, k = c sin(A). From the second equation k = asin(C). Hence.
asin(C) = csin(A) => divide both sides by "ac"
sin(C)/ c = sin(A)/a
Which is the law of sines for a triangle.
Thank you,
MrB
