The Answer:
The diameter will be reduced or shorten to prevent the induced current in the metal loop
explanation:
Magnetic flux is given as
Φ = BA•Cosθ
Since the angle is kept constant.
So to have same magnetic flux with larger magnetic field required only the diameter to changed
From the equation above,
Φ = BA•Cosθ
B= Φ / A•Cosθ
Since both Flux and the angle is constant
Then, The magnetic field is inversely proportional to the Area
And the areas is a function of diameter, Area = πd²/4
So to have a larger magnetic field, we need to reduce or shorten the diameter.
As d reduces, B increases.
Answer:
The magnitude of the magnetic field near the center of the solenoid is 11.3 mT
Explanation:
No. of turns 
Radius 
m
Length of solenoid 
m
Current 
A
For finding the magnetic field near the center of the solenoid is given by,
Where 
T
mT
Therefore, the magnitude of the magnetic field near the center of the solenoid is 11.3 mT
Answer:
The object distance is 20cm
Explanation:
Given
Magnification = -1.5
Image distance = 30 cm.
Required
Object Distance
We can calculate the object's distance using magnification formula;
M = -V/U
Where M = Magnification = -1.50
V = Image Distance = 30cm
U = Object Distance
Substitute the above parameters in the formula above.
-1.50 = -30/U
Multiply both sides by -1
-1.50 * -1 = -30/U * -1
1.50 = 30/U
Multiply both sides by U
1.50 * U = 30/U * U
1.50U = 30
Divide through by 1.50
1.50U/1.50 = 30/1.50
U = 30/1.50
U = 20cm
Recall that U represented the object distance.
Hence, the object distance is 20cm
Answer:
-107 m
Explanation:
Sum of forces in the y direction:
∑F = ma
-qE = ma
a = -qE/m
a = -(1.60×10⁻¹⁹ C) (304 N/C) / (9.11×10⁻³¹ kg)
a = -53.4×10¹² m/s²
Given in the y direction:
v₀ = 0 m/s
a = -53.4×10¹² m/s²
t = 2×10⁻⁶ s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (2×10⁻⁶ s) + ½ (-53.4×10¹² m/s²) (2×10⁻⁶ s)²
Δy = -107 m
Answer:
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Explanation:
