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serious [3.7K]
4 years ago
8

An electromagnetic wave with an electric field that oscillates with a period of 8.43 ps is travelling in a vacuum. What is the w

avelength of this electromagnetic wave?
Physics
1 answer:
marysya [2.9K]4 years ago
5 0

"ps" stands for "pico-second".  It means 10⁻¹² second.

The period of this wave is 8.43 x 10⁻¹² second.

In a vacuum, the speed of any electromagnetic wave is 3 x 10⁸ m/s.

Wavelength = (speed) / (frequency)

But Frequency = 1 / period

So Wavelength = (speed) x (period)

Wavelength = (3 x 10⁸ m/s) x (8.43 x 10⁻¹² sec)

Wavelength = 2.5 x 10⁻³ meter

<em>Wavelength = 2.5 millimeters</em>

<em></em>

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Is a reflection matter?
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Answer:

Yes, because everything bounce off in every surface around any object.

Explanation:

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3 years ago
Which of the following is not an example of convection? Warm air rising from heated pavement The rolling motion of boiling water
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Answer: The handle of a frying pan on the stove

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The handle of a frying pan gets hotter but no molecular movement is done. It is between the same material there is a energy transfer from the source to the rest of the pan. This is called Conduction.

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3 years ago
Often times we think about insulation, we think about keeping cold items cold, such as drinks in an ice chest or the cool temper
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4 0
2 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
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Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

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3 years ago
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7 0
3 years ago
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