Answer:
![2.0 m/s^2](https://tex.z-dn.net/?f=2.0%20m%2Fs%5E2)
Explanation:
The figure is not provided and we don't know the force applied to the books.
Therefore, here we are going to assume the force applied is 3 N:
F = 3 N
We can find the acceleration of the stack of books by using Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where
F is the force
m is the mass
a is the acceleration
In this problem we have
m = 1.5 kg is the mass of the books
Therefore, the acceleration is:
![a=\frac{F}{m}=\frac{3.0}{1.5}=2.0 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF%7D%7Bm%7D%3D%5Cfrac%7B3.0%7D%7B1.5%7D%3D2.0%20m%2Fs%5E2)
Answer:
2.11 m
Explanation:
<u>Given data</u>
h=6.626×
(plank constant)
L=45.7 pm
n=n2-n1
n=5-1
n=4
<em>where,</em>
<em>n2=5</em>
<em>n1=1</em>
<u>To find:</u>
E=?
λ=? (Wavelength)
<u>solution</u>
The energy stored in an electron at a specified level is given by;
E=
×
÷8m
..........(1)
<em>m=mass of electron(9.1×</em>
)
<em>l=length of box</em>
<u>To find E</u>
putting the value of given data in eq(1)
E=9.41×![10^{-16}](https://tex.z-dn.net/?f=10%5E%7B-16%7D)
<u>To find λ</u>
λ=hc/E............................(2)
c=3×
(speed of light)
putting the value in eq 2 to find wavelength
λ=2.11 m
<u></u>
<u>Note:</u>
There is a chance in calculation error. but the method is correct to solve the problem.
You don't need to do any calculations, you are already given that n=1.5
n is index of refraction. it's 1.5
Given:
u = 8.5 cm
f = -14.0 cm
v = image distance
Using the mirror formula 1/u + 1/v = 1/f
1/8.5 + 1/v = 1/-14.0
Rewrite to solve for v:
v = (8.5 * -14.0) / (8.5 - (-14.0))
v = -119 / 22.5
v = -5.29 cm ( round answer as needed.)
I can help you, but what is “the following” of answer choices that go along with the question?