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ipn [44]
3 years ago
7

Exercises 1–5

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Answer:  The estimated value for population mean rating based on these ten sampled ratings is 7.3 .

Step-by-step explanation:

Given : A random sample of size ten produced the following ratings in the computer games rating example in the  last lesson:

12, 5, 2, 4, 1, 4, 18, 10, 1, 16.

Let x denotes any value in the above data.

{\sum_{i=1}^{10}x_i}{10}=73

We know that the sample mean(\overline{x}) is the best estimate to the population mean(\mu).

Sample mean=\overline{x}=\dfrac{\sum_{i=1}^{n}x_i}{n}

Here , n= 10

\overline{x}=\dfrac{\sum_{i=1}^{10}x_i}{10}

\overline{x}=\dfrac{73}{10}=7.3

Therefore , the estimated value for population mean rating based on these ten sampled ratings= 7.3

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What are the correct answers and why? Simple and concise explanation please!!!
dezoksy [38]

Answer:

\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}

Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

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-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8

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-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4

In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.

6 0
3 years ago
Read 2 more answers
Find the slope of the line passing through the points (-7 ,-7) and (-3,6)
ycow [4]

Answer:

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Step-by-step explanation:

6 - (-7)

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6 0
2 years ago
Need help with #11. The answer is about 13.86 years but show work please.
tangare [24]

Answer:

13.86

Step-by-step explanation:

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sub in to get:

10000 = 5000e^0.05t

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6 0
3 years ago
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Answer:

Step-by-step explanation:

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victus00 [196]

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H

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