The answer choices are sufficiently far apart that you can work this backward. The sum will be ...
236,196*(1 + 1/3 + 1/9 + 1/27 + ...)
so a reasonable estimate can be given by an infinite series with a common ratio of 1/3. That sum is
236,196*(1/(1 - 1/3)) = 236,196*(3/2)
Without doing any detailed calculation, you know the best answer choice is ...
354,292
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There are log(236196/4)/log(3) + 1 = 11 terms* in the series, so the sum will be found to be 4(3^11 -1)/(3-1) = 2*(3^11-1) = 354,292.
Using the above approach (working backward from the last term), the sum will be 236,196*(1-(1/3)^11)/(1-(1/3)) = 236,196*1.49999153246 = 354,292
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* If you just compute log(236196/4)/log(3) = 10 terms, then your sum comes out 118,096--a tempting choice. However, you must realize that the last term is larger than this, so this will not be the sum. (In fact, the sum is this value added to the last term.)
Answer: -2/3
3-(-1) over
-2-4
This equals 4/-6 which reduces to -2/3
All you need to do is replace the variables with the numbers given.
t=9 & u=11
3+ 11t - 9u
3+ 11(9)-9(11)
3+ 99 - 99
The 99's cancel each other out, so you are left with 3.
The answer is 3.
To fine one gallon:
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Answer: 1 gallon can traveled 29 miles---------------------------------------------------------------
