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makkiz [27]
3 years ago
14

You are reviewing new RAM to purchase for a gaming computer and find three different RAM modules that are the same except for th

eir CAS Latency. Option A lists the CL as 18 ns, Option B lists the CL as 20 ns, and Option C lists the CL as 15 ns.
Computers and Technology
1 answer:
Gennadij [26K]3 years ago
4 0

Answer:

The review will state that the Option C RAM ( with CAS Latency 15 ) will the most efficient one among the three, Option A list will be moderately efficient and Option B will have least efficient RAM.

Explanation:

CAS Latency is actually Clock Address Strobes that defines the number of clock cycles the RAM takes to make the specified data available to its pins from where the data is than read by the processor for its usage. So, the greater the CAS Latency ( often specified as xyz ns ) the less efficient the RAM is. That's why in the review it will be Option C list Ram with least CAS Latency to be choose as maximum efficient.

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Answer:

The answer of this question is given below into explanation section

Explanation:

answer (a)

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3 years ago
Imagine that you need to be late to work next Thursday because of a doctor's appointment. Compose your own e-mail appropriate fo
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In form your boss a week early
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What HTML tag would you use to indicate a line break?
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<br> APEX Verified

Explanation:

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Write a program that computes the minimum, maximum, average and standard deviation of the population over time for a borough (en
IrinaK [193]

Answer:

import pandas as pd #importing pandas library as pd

import matplotlib.pyplot as plt #importing matplotlib.pyplot as plt

pop=pd.read_csv('nycHistPop.csv') #reading the csv file

borough=input('Enter borough name:') #asking the user for borough namme

# image=input('Enter image name:')

# pop['Fraction']=pop[borough]/pop['Total']

# pop.plot(x='Year', y='Fraction')

print("Minimum population",pop[borough].min()) #printing the minimum population of borough

print("Maximum population",pop[borough].max()) #printing the maximum population of borough

print("Average population",pop[borough].mean()) #printing the average population of borough

print("Standard deviation",pop[borough].std()) #printing the standard deviation of borough

# fig=plt.gcf()

# fig.savefig(image)

Explanation:

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3 years ago
You notice that somehow you have duplicate records for some of your clients in your database. What should you do?
IRINA_888 [86]

Inspect them and make sure that they are exact copies then delete one if they are the same.

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