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ololo11 [35]
3 years ago
6

When examining the distribution of a single variable, we look at shape, center, spread, and outliers. When examining the relatio

nship between two quantitative variables, we look at form, direction , __________, and outliers.
Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

When examining the distribution of a single variable, we look at shape, center, spread, and outliers. When examining the relationship between two quantitative variables, we look at form, direction, <u>Strength</u>, and outliers.

Step-by-step explanation:

  • When examining the relationship between two quantitative variables, we look at form, direction, strength and outliers.  
  • Because we want to know if the relationship is strong (a clear pattern) or weak (no pattern is really evident).
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A manufacturing process that produces electron tubes is known to have a 10% defective rate. Suppose a random sample of 15 tubes
posledela

Answer:

Probability of obtaining no more than two defective tubes = 0.816

Step-by-step explanation:

The Probability of obtaining no more than two defective tubes in a randomly selected sample of 15 tubes is obtained using the binomial distribution formula: nCr × p^r × q^(n -r).

Where n is number of samples;

r is maximum number of defective tubes, r ≤ 2;

p is probability of defective tubes = 10% or 0.1

q is probability of non-defective tubes, q = 1 - p

Further explanations and calculations are given in the attachment below:

3 0
4 years ago
Help me out here pleaseeeeeeee
vazorg [7]

Answer: 3\frac{1}{5}

have: 6\frac{1}{2}=6.5;\\\\3\frac{3}{10}=3.3

Syd ran than Jose: 6.5-3.3=3.2=\frac{16}{5}=3\frac{1}{5} (miles)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Point B has coordinates ​(2​,1​). The​ x-coordinate of point A is -10 . The distance between point A and point B is 13 units. Wh
Paraphin [41]

hmmm we know B (2 , 1), and let's say the y-coordinate is "y" for A, so A (-10 , y).

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{-10}~,~\stackrel{y_2}{y})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BA=\sqrt{[-10 - 2]^2 + [y - 1]^2}\implies 13=\sqrt{(-12)^2+(y^2-2y+1)} \\\\\\ 13^2=(-12)^2+(y^2-2y+1)\implies 169=144+y^2-2y+1 \\\\\\ 169=y^2-2y+145\implies 0=y^2-2y-24 \\\\\\ 0=(y-6)(y+4)\implies y= \begin{cases} 6\\ -4 \end{cases}~\hfill A= \begin{cases} (-10~,~6)\\ (-10~,~-4) \end{cases}

8 0
3 years ago
Using a calculator, find the decimal equivalent for the fraction 416888 416 888 . CLEAR CHECK 0.468⎯⎯ 0 . 46 8 ¯ 0.468 0 . 468 0
vlabodo [156]
<h3>Decimal equivalent for the fraction can be written as \overline{0.468468}</h3>

Step-by-step explanation:

Here, the given fraction that needs to be divided is:

P = (\frac{416}{888} )

Now, here the dividend is given as : 416

The Divisor is given as: 886

Also, as Divisor > Dividend

⇒ <u>The quotient will be less than 1.</u>

Now, if we use the calculator to find the decimal equivalent of P , we get:

P = (\frac{416}{888} )  = 0.4684684684..

Noe, as we can see, the group number (468468) is repeated non terminating.

So, the solved quotient can be written as : \overline{0.468468}

Hence, decimal equivalent for the fraction can be written as \overline{0.468468}

8 0
3 years ago
Read 2 more answers
Write an equation for the vertical translation y=-2/9 |x| -7; 1 units down
klasskru [66]

Answer:

y = -2/9 |X| - 8

Step-by-step explanation:

I'm not certain whether the -7 is part of the |X| or it's just out of the equation. But shifting an equation up or down is very intuitive.

If you want to move an equation up a certain unit, you just add that many units (positive) onto the end of an equation. The same goes for moving a unit down, where you subtract that many units you want to go down.

8 0
3 years ago
Read 2 more answers
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