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3 years ago

Write an equation for the vertical translation y=-2/9 |x| -7; 1 units down

Mathematics

2 answers:

klasskru [66]3 years ago

8 0

Answer:

y = -2/9 |X| - 8

Step-by-step explanation:

I'm not certain whether the -7 is part of the |X| or it's just out of the equation. But shifting an equation up or down is very intuitive.

If you want to move an equation up a certain unit, you just add that many units (positive) onto the end of an equation. The same goes for moving a unit down, where you subtract that many units you want to go down.

natima [27]3 years ago

8 0

Answer:

y=-2/9 |x| -8

Step-by-step explanation:

y = f(x) + C C < 0 moves it down

y=-2/9 |x| -7 Shift down 1 by subtracting 1

y=-2/9 |x| -7-1

y=-2/9 |x| -8

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max2010maxim [7]

Answer:

Volume = ( About ) 2406.165 cm^3

Step-by-step explanation:

If you consider a cube or a rectangular prism, you could identify it's volume through the multiplication of it's Base by height. A pyramid has 1 / 3rd that volume, so in order to take a volume of the figure to the left, we would multiply Base * height and take 1 / 3rd of that;

$Square Pyramid,\\Base ( Square ) = a^2, a = length = 17.2 cm\\Height = 24.4 cm\\\\Volume = 1 / 3 ( Base ) ( Height ),\\Volume = 1 / 3 ( ( 17.2 )^2 )( 24.4 ),\\Volume = 1 / 3( 295.84 )( 24.4 ),\\\\Volume = 98.6133333333( 24.4 ),\\Volume = 2406.16533333,\\\\Volume = ( About ) 2406.165$

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pav-90 [236]

Answer:

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Step-by-step explanation:

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Sedaia [141]

Answer:

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Step-by-step explanation:

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Keiko has seven colors of lanyard. She uses three different colors to make a keychain. How many different combinations can she c

AleksAgata [21]

Combination = doesn't matter what order
Permutation = order matters

There are two methods to work out combinations.

Method 1 List out possibilities
123 124 125 126 127 134 135 136 137 145 146 147 156 157 167
234 235 236 237 245 246 247 256 257 267
345 346 347 356 357 367
456 457 467
567

For a total of 35 combinations.

Method 2 Use a formula.
It's a rather complicated one, so only use it if you have a lot of possibilities.

$\frac{n!}{r!(n-r)!} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!*4!} = \frac{7*6*5*4*3*2*1}{3*2*1*4*3*2*1} = \frac{7*6*5}{3*2*1}=\frac{210}6=35$

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3 years ago