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3 years ago

Write an equation for the vertical translation y=-2/9 |x| -7; 1 units down

Mathematics

2 answers:

klasskru [66]3 years ago

8 0

Answer:

y = -2/9 |X| - 8

Step-by-step explanation:

I'm not certain whether the -7 is part of the |X| or it's just out of the equation. But shifting an equation up or down is very intuitive.

If you want to move an equation up a certain unit, you just add that many units (positive) onto the end of an equation. The same goes for moving a unit down, where you subtract that many units you want to go down.

natima [27]3 years ago

8 0

Answer:

y=-2/9 |x| -8

Step-by-step explanation:

y = f(x) + C C < 0 moves it down

y=-2/9 |x| -7 Shift down 1 by subtracting 1

y=-2/9 |x| -7-1

y=-2/9 |x| -8

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Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak

crimeas [40]

Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

$\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353$

We can calculate the z values for x1=0.47 and x2=0.51:

$z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28$

We can now calculate the probabilities:

$P(0.47$

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

$\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05$

We can calculate the z values for x1=0.47 and x2=0.51:

$z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2$

We can now calculate the probabilities:

$P(0.47$

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

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3 years ago

What is 2 dollars to 40 cents as a fraction in lowest terms?

pav-90 [236]

It is 5/1
200/40
20/4
5/1

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3 years ago

Ty received test grades of 82%, 74%, 76%, 76%, and 74%.

Nikitich [7]

Answer:

a) To earn C he needs at least 68 and less than 98

b) No, he couldn't make it.

Step-by-step explanation:

I. His avg value is (382 + x)/6

I pick a random number and that gave

(68 => to reach 75) and (98 => to reach 80)

So that makes he needs at least 68 and less than 98

II. The reason why he cannot make it is

if 100 is 100%

= (100 + 382)/6

= 80.33 That's impossible to reach 90

Hope that help :)

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3 years ago

Given the following exponential function, identify whether the change represents growth or decay, and

cestrela7 [59]

Answer: 97% growth rate.

Step-by-step explanation:

Hi, to answer this question we have to analyze exponential function:

A = P (1 + r) t

Where:

p = initial value

r = growth or decay rate (decimal form)

t= number of time intervals

A = value after t intervals

Replacing with the values given:

y=3400(1.97)^x

Where the term 1.97 = 1 + r

Solving for r:

1.97-1 = r

0.97 =r

Since the rate is positive, it is a growth rate.

To determine the percentage we have to multiply it by 100

0.97 x 100 = 97%

Feel free to ask for more if needed or if you did not understand something.

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3 years ago

Use a truth table to determine whether to two statements are equivalent

I am Lyosha [343]

Answer:

equivalent yan kasi pareho lang den nmn letters lng naiba

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3 years ago