Answer:
Width = 2
Length = 5
Step-by-step explanation:
let A be the area of the rectangle
L be the length of the rectangle
w be the width of the rectangle
<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’
A = L × w
…………………………………………………
A = L × w
⇔ 10 = (w + 3) × w
⇔ 10 = w² + 3w
⇔ w² + 3w - 10 = 0
<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 = 0 :
Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49
then √Δ = 7
-5 is not valid ,because w represents the width
which must be a positive number
Then w = 2
<u><em>Conclusion</em></u>:
Width = 2
Length = 2 + 3 = 5
X =
First, before we can add, we have to find a common denominator.
We can use 24.
7 7/8 x 3/3 = 7 21/24
2 1/3 x 8/8 = 2 8/24
Now we add.
7 21/24 + 2 8/24 = 9 29/24 (denominator stays the same)
Lastly, simplify
9 29/24 = 10 5/24
Hope this helps
Answer:
33
Step-by-step explanation:
1. (x-10)+67=90 because it's a 90 degree angle
2.subtract 67: x-10=23
3. add 10: x=33
Im not sure but you cam try adding 15+9 which is 24
Hello!
We know that the formula for perimeter of a rectangle is:
P = 2l + 2w
We've been given enough information to solve this question!
The perimeter of the rectangle is 60 metres, and the its length is 14 meters long.
We must multiply the length by 2 and then subtract it from the perimeter to find the width.
W = P - 2l
W = 60 - 2(14)
W = 32
Therefore, the width of the rectangle is 32 metres long.
