The correct order given below shows the changes that occurs in a mice population in response to changes in their environment:
- The population of mice is in an environment with many black rocks
- Mice with black for are more likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have black fur
- A sandstorm covers most of the population's environment with brown sand
- Mice with black fur are less likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have brown fur
<h3>What is the correct order for natural selection in the desert environment given?</h3>
Based on the process of natural selection due to envrionmental pressures, the population of the mice in the desert changes as follows before and after the environmental change:
- The population of mice is in an environment with many black rocks
- Mice with black for are more likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have black fur
- A sandstorm covers most of the population's environment with brown sand
- Mice with black fur are less likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have brown fur
Therefore, the correct order shows the changes that occurs in a mice population in response to changes in their environment.
Learn more about about adaptation at: brainly.com/question/25594630
Oxygen:
Atomic no. = 8(from periodic table)
⇒1s^2 2s^2 2p^4
But it is O^2-
There are 2 more electrons
=>1s^2 2s^2 2p^6
Voila!
I can describe one prop. of energy: it can not be created or destroyed. It can be transferred, or converted, though.
Answer:
3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂
Explanation:
The balanced reaction is:
SOCl₂ + H₂O ----> SO₂ + 2 HCl
By stoichiometry of the reaction they react and produce:
- SOCl₂: 1 mole
- H₂O: 1 mole
- SO₂: 1 mole
- HCl: 2 mole
Being:
- S: 32 g/mole
- O: 16 g/mole
- Cl: 35.45 g/mole
- H: 1 g/mole
the molar mass of the compounds participating in the reaction is:
- SOCl₂: 32 g/mole + 16 g/mole + 2*35.45 g/mole= 118.9 g/mole
- H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
- SO₂: 32 g/mole + 2*16 g/mole= 64 g/mole
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
Then, by stoichiometry of the reaction, the following amounts of mass react and are produced:
- SOCl₂: 1 mole* 118.9 g/mole= 118.9 g
- H₂O: 1 mole* 18 g/mole= 18 g
- SO₂: 1 mole* 64 g/mole= 64 g
- HCl: 2 mole* 36.45 g/mole= 72.9 g
Then the following rule of three can be applied: if by stoichiometry of the reaction 118.9 grams of SOCl₂ produce 2 moles of HCl, 0.226 grams of SOCl₂ how many moles of HCl do they produce?
moles of HCl= 3.80*10⁻³
<u><em>3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂</em></u>
Answer:
d. 10 million years
Explanation:
These are the options for the question
Choose one answer.
a. 2.5 million years
b. 5 million years
c. 15 million years
d. 10 million years
✓half-life of the radioactive substance= 5 million years
✓ Then for every 5 million years, original radioactive given (100%) percentage is reduced by factor of 1/2.
✓ 1st 5 million year; After the first 5 million years, the original radioactive is reduced as;
(100%) × 1/2 = 50% remains
✓2nd 5 million year: At 10 millions year, the 50% remaining radioactive is reduced by factor of 1/2
(50%) × 1/2 = 25% remains
Hence, at At 10 millions years 25% of the original radioactive atoms remain
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