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Artyom0805 [142]
3 years ago
6

V2O5 + Ca = V + CaO balance the eqaution

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer: The balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, V_{2}O_{5} + Ca \rightarrow V + CaO

Here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 1

The number of atoms on product side are as follows.

  • V = 1
  • O = 1
  • Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO

Now here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

The number of atoms on product side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

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Explanation:

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M 0.103 M of NaOH,

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Now,

⇒  mol of NAOH = MV

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Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

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Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

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3 years ago
If the number of moles of a gas initially contained in a 2.10 l vessel is doubled, what is the final volume of the gas in liters
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V -volume and n - number of moles of gas.
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
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V2 - final volume - V
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Explanation:

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