9514 1404 393
Answer:
C
Step-by-step explanation:
Corresponding angles are listed in the same order in the mapping statement.
C' is the third vertex named in A'B'C'D'. It corresponds to the third vertex named in ABCD, which is C.
angle C' corresponds to angle C
Step-by-step explanation:
x⁴ − 5x³ + 11x² − 25x + 30
x⁴ − 5x³ + 6x² + 5x² − 25x + 30
x² (x² − 5x + 6) + 5 (x² − 5x + 6)
(x² + 5) (x² − 5x + 6)
(x² + 5) (x − 2) (x −3)
The zeros are 2, 3, and ±√5i.
The answer is 0, hope it helps lol
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
Answer:
t=11,11 days
Step-by-step explanation:
F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating
⇒ LnF=Kt+c,
; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)),
⇒
, so
, now if F=130, t=? we have:
