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Sergeeva-Olga [200]
4 years ago
9

A 2500-lb vehicle has a drag coefficient of 0.35 and a frontal area of 20 ft2. What is the minimum tractive effort required for

this vehicle to maintain a 70 mi/h speed on a 5% upgrade through an air density of 0.002045 slugs/ft3?
Physics
1 answer:
emmasim [6.3K]4 years ago
4 0

Answer:

i put this in the calculator and my answer is 600. hope this helps

Explanation:

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MA_775_DIABLO [31]

Answer:

first you have to

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3 0
3 years ago
The solar system is made up of eight planets, numerous comets, asteroids and moons, and the Sun. The force that holds all of the
s2008m [1.1K]

Your answer is Gravity


Hope this could help :)

5 0
3 years ago
What does a Lewis structure diagram represent?
densk [106]

Answer:

correct me if i'm wrong nut i thinks its a The atomic symbol of an element surrounded by valence electrons

Explanation:

5 0
3 years ago
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What if The rotational speed of Earth increased ?
dsp73

Answer:

This would happen.

Explanation:

If the earth’s rotation speed increases then the weight of the body decreases. This is because you see a moving body on the rotating earth’s surface itself is in the reference frame. So when the earth rotates, the centripetal force acts towards the centre of rotation.

4 0
3 years ago
You hang a heavy ball with a mass of 30 kg from a tungsten rod 2.8 m long by 1.5 mm by 2.6 mm. You measure the stretch of the ro
guajiro [1.7K]

Answer:

Young's modulus (Y) = 3.56×10^11 N/m^2

The speed of sound in tungsten = 6166.4 m/s

Explanation:

Young's modulus (Y) = stress/strain

Stress = force/area

Force = mg = 30×9.8 = 294 N

Area = 1.5 × 2.6 = 3.9 mm^2 = 3.9/10^6 = 3.9×10^-6 m^2

Stress = 294/3.9×10^-6 = 7.54×10^7 N/m^2

Strain = extension/length

Extension = 0.000594 m

Length = 2.8 m

Strain = 0.000594/2.8 = 2.12×10^-4

Y = 7.54×10^7/2.12×10^-4 = 3.56×10^11 N/m^2

Y = h × rho × g

rho = 18.7 g/cm^3 = 18.7 g/cm^3 × 1 kg/1000 g × (100 cm/1 m)^3 = 18,700 kg/m^3

h = 3.56×10^11/(18,700×9.8) = 1.94×10^6 m

From the equations of motion

v^2 = u^2 + 2gh =

Initial speed (u) = 0 m/s

v = sqrt (2×9.8×1.94×10^6)

v = 6166.4 m/s

7 0
4 years ago
Read 2 more answers
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