I can why do plants grow fast?
You should write ' 4 ' in the first box,
and ' m/s² ' in the second box.
Answer: 217.52 N
Explanation: The applied force is 20 N, the distance covered is 12.0 m and the angle is 25° above the horizontal.
Hence the formulae that defines work done is given by
W = Force × distance
But since the force has been inclined at an angle θ above the horizontal, the horizontal component of force is neccesary to produce the required motion to make the child do work on the wagon.
Hence
Work done = (horizontal component of force) × distance
Work done = F cos θ × distance
Work done = 20 cos 25 × 12 = 217.52 N
Answer:
Explanation:
We can solve the problem by using Kepler's third law, which states that the ratio between the cube of the orbital radius and the square of the orbital period is constant for every object orbiting the Sun. So we can write
where
is the distance of the new object from the sun (orbital radius)
is the orbital period of the object
is the orbital radius of the Earth
is the orbital period the Earth
Solving the equation for , we find
![r_o = \sqrt[3]{\frac{r_e^3}{T_e^2}T_o^2} =\sqrt[3]{\frac{(1.50\cdot 10^{11}m)^3}{(365 d)^2}(180 d)^2}=9.4\cdot 10^{10} m](https://tex.z-dn.net/?f=r_o%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Br_e%5E3%7D%7BT_e%5E2%7DT_o%5E2%7D%20%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%281.50%5Ccdot%2010%5E%7B11%7Dm%29%5E3%7D%7B%28365%20d%29%5E2%7D%28180%20d%29%5E2%7D%3D9.4%5Ccdot%2010%5E%7B10%7D%20m)
(c) When the two pulses completely overlap on the string forms a straight line.
A single disturbance that travels via a transmission medium is referred to as a pulse. This medium might be formed of stuff or a vacuum, and it might be endlessly large or finite in size.
Consider two pulses that are identical in shape and proceed in opposite directions along a string, with the exception that one has positive displacements of the string's elements while the other has negative displacements.
On the string, the two pulses blend together completely.
The pulses completely balance one another out in terms of removing string elements from equilibrium, yet the string still moves. Shortly after the string is once again shifted, the pulses will have passed each other.
The correct option is (c)
Learn more about pulse here:
brainly.com/question/14885673
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