There are 2.32 x 10^6 kg sulfuric acid in the rainfall.
Solution:
We can find the volume of the solution by the product of 1.00 in and 1800 miles2:
1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m
1.00 in * 1 m / 39.3701 in = 0.0254 m
Volume = 4.662 x 10^9 m^2 * 0.0254 m
= 1.184 x 10^8 m^3 * 1000 L / 1 m3
= 1.184 x 10^11 Liters
We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70:
[H+] = 10^-pH = 10^-3.7 = 0.000200 M
[H2SO4] = 0.000100 M
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid:
1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4
We can now calculate for the mass of sulfuric acid in the rainfall:
mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
= 2.32 x 10^9 g * 1 kg / 1000 g
= 2.32 x 10^6 kg H2SO4
Answer:
left, increase
Explanation:
If oxygen gas is removed from the system, then the equilibrium will shift to the __left_____ and the amount of NH3 gas will _increase________.
Order of Solubility of given alcohols is as follow,
Ethanol Butanol Hexanol
Highly Soluble ---------->--------------------->------------------------>---Slightly Soluble
As we know Like dissolves Like. Water is a polar solvent and dissolves readily those compounds which are polar in nature. The solubility of all these alcohols is due o the -OH (hydroxyl) group which tends to form Hydrogen Bond interactions with the water molecules. The difference comes in the alkyl group of these compounds. The akyl group is non polar in nature and immiscible in water. As the non polar chain increases from ethanol to hexanol, so the solubility also decreases from ethanol to hexanol.
Answer:
1.20 M (3 s.f.)
Explanation:
In this question, we are trying to find the concentration of KCl after dilution. Note that the number of moles of KCl does not change.
Number of moles of KCl
= 44.7 ÷74.55
= 0.59960 mol (5 s.f.)
New volume
= 500 mL
= (500 ÷1000) L
= 0.5 L
Concentration after dilution
= 0.59960 ÷0.5
= 1.1992 mol/L
= 1.20 M (3 s.f.)
* M is the symbol for Molarity, which is also equal to mol/L
