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Mrrafil [7]
2 years ago
6

At room temperature (20°C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

n that of air. In a buoyancy experiment with a new plastic, a chemist creates a rigid, thin-walled ball that weighs 0.12 g and has a volume of 560 cm⁹.
(c) Will it float if filled with hydrogen (d = 0.0899 g/L)?
Chemistry
1 answer:
Eduardwww [97]2 years ago
8 0

Total density of filled ball with hydrogen gas: \frac{0.12g+0.050344g}{0.560L} = 0.3041g/L

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

Density of hydrogen gas = d_2 = 0.0899g/L

Mass of the hydrogen gas : \frac{0.12g+0.050344}{0.560L} = 0.3041g/L

Learn more about Mass and Density here:

brainly.com/question/10821730

#SPJ4

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choli [55]

Hello,

That is true.

8 0
3 years ago
Read 2 more answers
A gas mixture contains 10.0 mole% H2O (v) and 90.0 mole % N2. The gas temperature and absolute pressure at the start of each of
Rainbow [258]

Answer: (a). T = 38.2 °C     (b). V = 1.3392 cm³     (c). ii and iii  

Explanation:

this is quite easy to solve, i will give a step by step analysis to solving this problem.

(a). from the question we have that;

the Mole fraction of Nitrogen, yи₂ = 0.1

Also the Mole fraction of Water, yн₂o = 0.1

We know that the vapor pressure is equal to the partial pressure because the vapor tends to condense at due point.

ρн₂o = ṗн₂o

      = yн₂oP = 0.1 × 500 mmHg = 50 mmHg

from using Antoine equation, we apply the equation

logρн₂o = A - B/C+T

T = B/(A - logρн₂o) - C

  = 1730.63 / (8.07131 - log 50mmHg) - 223.426

T = 38.2 °C

We have that the temperature for the first drop of liquid form is 38.2 °C

(b). We have to calculate the total moles of gas mixture in a 30 litre flask;

   n  = PV/RT  

   n = [500(mmHG) × 30L] / [62.36(mmHGL/mol K) × 323.15K] = 0.744 mol

Moles of H₂O(v) is 0.1(0.744) = 0.0744 mol

Moles of N₂ is 0.9(0.744) = 0.6696 mol

we have that the moles of water condensed is 0.0744 mol i.e the water vapor  in the flask is condensed

Vн₂o = 0.0744 × 18 / 1 (g/cm³)

Vн₂o = 1.3392 cm³

Therefore, the  volume of the liquid water is 1.3392 cm³

(3). (ii) and (iii)

The absolute pressure of the gas and The partial pressure of water in the gas would change if the barometric pressure drops.

cheers i hope this helps!!!!

4 0
3 years ago
How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?
nevsk [136]

Answer:

17.5 g

Explanation:

Given data

  • Mass of solution to be prepared: 50.0 grams
  • Concentration of the salt solution: 35.0%

The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl

4 0
3 years ago
A lab is done using different metals and the density of the metals are recorded in a data table. What is the independent variabl
vovikov84 [41]

Answer:   The independent variable is the type of metal being used.

{Note:  The "dependent variable" is the "measured density" that corresponds to each of the metals."}.

___________________________________________

Explanation:

___________________________________________

The "independent variable", which is plotted on the "x-axis" (horizontal axis), is the variable that can be "controlled/manipulated".  In this case, this would be the type of metal chosen.

The "dependent variable" , which is plotted on the "y-axis" (vertical axis) is the "obtained value/measurement/result" (that "cannot be controlled/manipulated").

In this case, the "density", which is the "measured value" that corresponds to the selected "meal", is the "dependent variable".

___________________________________________

Hope this helpful to you!

   Wishing you well!

___________________________________________

6 0
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Agustina was standing on the edge of a cliff of unknown height holding a bowling ball. She wanted to find the height of the clif
nlexa [21]

Answer:

433 m

Explanation:

Since the fall represents motion under gravity, we use the equation

s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².

So, substituting the values of the variables into the equation, we have

s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²

s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²

s = 1/2(865.928 m)

s = 432.964

s ≅ 433 m

5 0
3 years ago
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