A way to charge insulators and conductors (the answer in 7 alphabets)

A point charge q1q1 is held stationary at the origin. A second charge q2q2 is placed at point aa, and the electric potential ene

Yuri [45]

Explanation:

The given data is as follows.

$U_{a} = 5.4 \times 10^{-8} J$

$W_{/text{a to b}} = -1.9 \times 10^{-8} J$

Electric potential energy ( $U_{b}$ ) = ?

Formula to calculate electric potential energy is as follows.

$U_{b} = U_{a} - W_{/text{a to b}}$

= $5.4 \times 10^{-8} J - (-1.9 \times 10^{-8} J)$

= $7.3 \times 10^{-8} J$

Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is $7.3 \times 10^{-8} J$ .

6 0

3 years ago

1. Does the validity of the principle of conservation of momentum depend on the validity of Newton's 3rd law of motion?

OverLord2011 [107]

I truly believe so, that’s a definite yes

8 0

3 years ago

How does a change in resistance affect the conductivity of a material?

max2010maxim [7]

Answer: the answer is B the lower the resistance,the higher the conductivity

Explanation:

Resistance is inversely proportional to conductivity,the lower the resistance the higher the conductivity,the metal silver has a very low resistance,thus it conductivity is high

4 0

3 years ago

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What do we mean by the event horizon of a black hole?

TEA [102]

<h2>Answer:</h2>

The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.

That is, at this border also called "point of no return", nothing can escape (not even light) and no event that occurs within it can be seen from outside.

5 0

3 years ago

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A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if

Dmitrij [34]

To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

$F_p = 6*10^{22}N$