<span>the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration</span>
Answer:
Away from the normal
Explanation:
The direction toward which the ray of light bend can be found by using Snell's law:

where
n1, n2 are the index of refraction of the first and second medium
are the angle of the incident and refracted ray with respect to the normal to the surface
Here, the ray of light moves from a material with high index of refraction to a material with lower index, therfore we have

Re-arranging Snell's equation we get

and since

we find

which means that the ray of light bends away from the normal.
Answer:
2.846m
Explanation:
The diver is performing projectile motion.
To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)
x(initial) = 0
x(final) = ?
v(initial) = 2.3 m/s
we don't know t
To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)
- 9.8 in the acceleration in the y dir.
y(final) = 0
y(initial) = 7.5
v(initial in the y dir.) = 0
If we solve for t we get: t = 1.237s
Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)
x(final) = 2.3*1.237 + 0
x(final) = 2.846m
Answer:
is their a picture or something
Explanation:
Answer:
a = 2.72 [m/s2]
Explanation:
To solve this problem we must use the following kinematics equation:

where:
Vf = final velocity = 1200 [km/h]
Vo = initial velocity = 25 [km/h]
t = time = 2 [min] = 2/60 = 0.0333 [h]
1200 = 25 + (a*0.0333)
a = 35250.35 [km/h2]
if we convert these units to units of meters per second squared
![35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]](https://tex.z-dn.net/?f=35250.35%5B%5Cfrac%7Bkm%7D%7Bh%5E%7B2%7D%20%7D%5D%2A%28%5Cfrac%7B1%7D%7B3600%5E%7B2%7D%20%7D%29%2A%5B%5Cfrac%7Bh%5E%7B2%7D%20%7D%7Bs%5E%7B2%7D%20%7D%20%5D%2A%28%5Cfrac%7B1000%7D%7B1%7D%20%29%2A%5B%5Cfrac%7Bm%7D%7Bkm%7D%20%5D%20%3D%202.72%20%5B%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%5D)