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Basile [38]
4 years ago
11

A bicyclist starts at point P and travels around a triangular path that takes her through points Q and R before returning to the

point P as shown here. What is the magnitude of her net displacement for the entire round trip? A. 100 m B. 200 m C. 600 m D. 1200 m E. zero
Physics
1 answer:
REY [17]4 years ago
4 0

Answer:

Displacement by cyclist is zero.

Explanation:

In the given question bicyclist is travelling in a rectangular track having P , Q and R edges.

The bicyclist starts from P and travel through Q and R and returned to P again.

We need to find its displacement.

We know displacement  of a body is its difference between its initial position to final position.

Here in the given question the bicyclist returns to P again.

Therefore, total displacement by bicyclist is zero.

Hence, this is the required solution.

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A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t
Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

KE = PE

\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

q_{1,2} = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}

Replacing,

q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}

q_2 = 3.6531nC

Therefore the charge on the sphere is 3.6531nC

4 0
3 years ago
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

I = F \Delta t

Where,

F = Force

\Delta t= Time

Our values are given as,

F = 1450N

\Delta t = 5.1*10^{-3} s

Replacing we have,

I = (1450)(5.1*10^{-3})

I = 7.395Kg\cdot m/s

Therefore the impulse delivered to the soccer ball is 7.395Kg\cdot m/s or  7.395N\cdot s

4 0
3 years ago
What happens when an electron moving from the 3rd energy level to the 1st energy level?
Sholpan [36]

Answer:

A photon of wavelength 103 nm is released

Explanation:

When an electron in an atom jumps from a higher energy level to a lower energy level, it releases a photon whose energy is equal to the difference in energy between the two levels.

For example, if we are talking about a hydrogen atom, the energy of the levels are:

E_1 = -13.6 eV\\E_2 = -3.4 eV\\E_3 = -1.5 eV

So, the energy of the photon released when the electron jumps from the level n=3 to n=1 is

\Delta E = E_3 - E_1 = -1.5 -(-13.6)=12.1 eV

In Joules,

\Delta E =12.1\cdot 1.6\cdot 10^{-19} = 1.94\cdot 10^{-18} J

We can also find the wavelength of this photon, using the equation:

\Delta E = \frac{hc}{\lambda}\rightarrow  \lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{1.94\cdot 10^{-18}}=1.03\cdot 10^{-7} m = 103 nm

7 0
4 years ago
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Nataly [62]

Answer:

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Explanation:

Condensation is the process by which water vapor in the air is changed into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds.

6 0
4 years ago
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Which is the formula for the functional group in an anime?
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The formula for the functional group is NH2

8 0
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