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Roman55 [17]
3 years ago
12

Ajar can hold 60 mL of liquid. It is 10 cm high and 2 cm wide. The length of the jar is:

Physics
2 answers:
ZanzabumX [31]3 years ago
8 0
60:2=30 despues 30:10= 3
marin [14]3 years ago
5 0

Answer:

3cm

Explanation:

From the question, we obtained the following:

Volume = 60mL = 60cm^3

Height = 10cm

Width = 2m

Length =?

Volume = length x width x height

Length = volume / width x height

Length = 60/(2 x 10) = 60/ 20

Length = 3cm

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A person riding a bike has a total mass of 95 kg, if the person bike system is moving at a velocity of 5 m/s, how much kinetic e
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Kinetic energy is 1187.5J

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Solar radiation is made up of light energy. Light energy can be separated by wavelength and frequency into the electromagnetic s
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Read 2 more answers
A skydiver free falls from rest. How long does it take for the skydiver to reach 7 m/s?
aev [14]

Answer:

<em>The skydiver needs 0.71 seconds to reach 7 m/s</em>

Explanation:

<u>Free Fall Motion </u>

When an object is dropped in free air (no friction) from a certain height h, it follows a free-fall motion, whose acceleration is due exclusively to gravity. The speed at a moment t when the object is dropped (from rest) is:

V_f=gt

We need to find How long does the skydiver needs to reach 7 m/s. We solve for t

\displaystyle t=\frac{V_f}{g}

\displaystyle t=\frac{7}{9.8}

t=0.71\ sec

The skydiver needs 0.71 seconds to reach 7 m/s

5 0
3 years ago
A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?
lara31 [8.8K]

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta (P_{tot}) experimentada por la persona es la suma de la presión atmosférica (P_{atm}) y la presión hidrostática de la columna de agua de la alberca (P_{h}), medidas en kilopascales. Es decir,

P_{tot} = P_{atm}+P_{h} (1)

P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000} (2)

Donde:

\rho - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

z - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que P_{atm} = 101.325\,kPa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} y P_{tot} = 156\,kPa, entonces la profundidad de la persona en la alberca es:

156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}

54.675 = 9.807\cdot z

z = 5.575\,m

La persona está nadando en la alberca a una profundida de 5.575 metros.

5 0
3 years ago
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