Answer:
1. B - Both are monbasic.
B - Both are monbasic.2. B - fast but contains more water than acid
B - Both are monbasic.2. B - fast but contains more water than acid3. D - Acids made from oxides of non metals
B - Both are monbasic.2. B - fast but contains more water than acid3. D - Acids made from oxides of non metals4. C. Zn(OH)2
B - Both are monbasic.2. B - fast but contains more water than acid3. D - Acids made from oxides of non metals4. C. Zn(OH)25. C - Neutralization
B - Both are monbasic.2. B - fast but contains more water than acid3. D - Acids made from oxides of non metals4. C. Zn(OH)25. C - Neutralization6. B - H3O+
Explanation:
According to reaserch,
According to reaserch,An neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products. In a neutralization reaction, there is a combination of H+ ions and OH– ions which form wa acid anhydride is an acid anhydride that is an organic compound.
According to reaserch,An neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products. In a neutralization reaction, there is a combination of H+ ions and OH– ions which form wa acid anhydride is an acid anhydride that is an organic compound. An acid anhydride is a compound that has two acyl groups bonded to the same oxygen atom.
Answer:
Im pretty sure it would be 23
Explanation:
If it divide asexually it would be identical
Answer:
I believe the answer is II and III
Explanation:
I'm not sure if III is right cause I cannot read the last word but I think it's OK.
Hope this helped :)
Answer : The amount left of leutium-176 will be, 2.10 g
Solution :
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the amount left of the sample.
Expression for rate law for first order kinetics is given by :
where,
k = rate constant =
t = decay time =
a = initial amount of the sample = 16.8 g
a - x = amount left after decay process = ?
Now put all the given values in above equation, we get
Therefore, the amount left of leutium-176 will be, 2.10 g
How advanced we’ve become in science and studying elements