Answer:
3.01 L
Explanation:
V
1
: 2.75L
T
1
:
18
∘
C
V
2
: ?
T
2
:
45
∘
C
If you know your gas laws, you have to utilize a certain gas law called Charles' Law:
V
1
T
1
=
V
2
T
2
V
1
is the initial volume,
T
1
is initial temperature,
V
2
is final volume,
T
2
is final temperature.
Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.
Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:
2.75
291
=
V
2
318
By cross multiplying, we have...
291
V
2
= 874.5
Dividing both sides by 291 to isolate
V
2
, we get...
V
2
= 3.005...
In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.
Therefore,
V
2
= 3.01 L
Chemical Formula of Sodium Sulfate is Na₂SO₄.
As we know, 1 mole of any substance contains 6.022 × 10²³ particles. So, 1 mole of Na₂SO₄ also contains 6.022 × 10²³ formula units of Na₂SO₄.
Also,
1 mole of Na₂SO₄ contains = 6.022 × 10²³ Atoms of S
So,
4.5 moles of Na₂SO₄ will contain = X atoms of S
Solving for X,
X = (4.5 moles × 6.022 × 10²³ Atoms) ÷ 1 mole
X = 2.70 × 10²⁴ Atoms of S
Result:
4.5 Moles of Na₂SO₄ contains 2.70 × 10²⁴ Atoms of Sulfur.
Answer:
500kg.
Explanation:
Newton's Second Law relates force, mass and acceleration to one another through the equation:
F = ma
We can rearrange this equation algebraically to solve for mass:
m = F/a
Substituting our known values for the variables, we get:
m = 1500N/3m/s2
So mass of the object is 500kg.
We know it's kg because Newtons (N) are a unit defined as 1 kg/m/s2, so m/s2 cancels out when we divide :)
Answer:
ok this is going to be a bit much but i will teach the basics. also this is an exothermic reaction
Explanation:
- concentration H2 increases: it shifts to the right. this decreases O2 and increase H2O and K stays the same
- concentration H2 decreases: it shifts to the left, it increases O2 and decreases H2O and K stays the same
- concentration of O2 increases: it shifts to the right, this decreases H2 and increase H2O and K remains the same
- concentration of O2 decreases: it shifts to the left. this increases H2 and decreases H2O and K stays the same
- concentration of H2O increases: it shifts to the left, this increases H2 and O2
- concentration of H2O decreases: it shifts to the right, this decreases H2 and O2
- temp. increase: shifts left, increase H2 and O2, decreases H20 and K decreases
- temp decrease: shifts right, decrease H2 and O2, increase H2O and K increases
- pressure increase: shifts right, decrease H2 and O2, increase H2O and K remains the same
ps i hope this helps. and i hope it isn't to confusing.
Sincerely, Marie
THE MOLECULE HAS A C=C AND AN -OH GROUP, SO IT IS CALLED AN ENE/OL, I.E., AN ENOL. ENOLS CAN BE FORMED ONLY FROM CARBONYL COMPOUNDS WHICH HAVE ALPHA HYDROGENS. THEY CAN BE FORMED BY ACID OR BASE CATALYSIS, AND ONCE FORMED ARE HIGHLY REACTIVE TOWARD ELECTROPHILES, LIKE BROMINE.
