Displacement = s = v1t +1/2at2
= 0 * 2.05 +1/2*(4.3)*(2.05^2)
= 0 + 9.04
= 9.04 m
The x component of the force on an incline plane is m*g*cos(theta) and the y component is mg*sin(theta). The normal force or x component, keeps the object in contact with the plane, and the y component of the force is so we can solve speed, acceleration, distance travelled, etc for the object using conservation of energy.
Hope this helps. Any questions please just ask. Thank you.
Answer:
a 15.22 m/s
b 45.65 m
Explanation:
Using the same formula,
x = vt, where
x is now 45.65, and
t is 3 s, then
45.65 = 3v
v = 45.65/3
v = 15.22 m/s
See the attachment for the part b. We used the distance gotten in part B, to find question A
It would take at less 10 minte i guess this the right awnser
To get this we need to know how long he was traveling. To know that we need to solve for the time it took for him to hit the ground. This is given by the vertical height he started at and the equation of motion for falling objects. The position function is
Y= -(9.8/2)t^2 + 50 = 0
t=3.19s
That's how long he's in the air. When he hits the ground he stops moving forward so this is also the amount of time he was moving at 100m/s horizontally. Now use speed distance relationship
X=vt
And solve for v
100m/3.19s = 31.35m/s
