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loris [4]
3 years ago
5

A student on an amusement park ride moves in a circular path with a radius of 3.5 meters once every 8.9 seconds. What is the ave

rage speed of the student
Physics
1 answer:
Ulleksa [173]3 years ago
7 0
Distance traveled by him = circumference of that circular path = 2πr = 2π(3.5)
= 7π = 7×3.14 = 21.98 m
time = 8.9 s  [ Given ]

Now, Average speed = distance / time
s = 21.98 / 8.9
s = 2.46 m/s

Hope this helps!
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Three balls are kicked from the ground level at some angles above horizontal with different initial speeds. All three balls reac
astra-53 [7]

Answer:

They all hit at the same time

Explanation:

Let the time of flight is T.

The maximum height is H and the horizontal range is R.

The formula for the time of flight is

T=\frac{2uSin\theta }{g} ..... (1)

Te formula for the maximum height is

H=\frac{u^{2}Sin^{2}\theta }{2g}    .... (2)

From equation (1) and (2), we get

\frac{T^{2}}{H}=\frac{\frac{4u^{2}Sin^{2}\theta }{g^{2}}}{\frac{u^{2}Sin^{2}\theta }{2g}}    

\frac{T^{2}}{H}=\frac{8}{g}

T=\sqrt{\frac{8H}{g}}

here, we observe that the time of flight depends on the maximum height and according to the question, the maximum height for all the three balls is same so the time of flight of all the three balls is also same.

8 0
3 years ago
What can you conclude about this product?
aksik [14]
What’s the question
6 0
4 years ago
A steel sphere sits on top of an aluminum ring. The steel sphere (a= 1.1 x 10^-5/degrees celsius) has a diameter of 4.000 cm at
Mars2501 [29]

Answer:

C

Explanation:

To solve this question, we will need to develop an expression that relates the diameter 'd', at temperature T equals the original diameter d₀ (at 0 degrees) plus the change in diameter from the temperature increase ( ΔT = T):

d = d₀ + d₀αT

for the sphere, we were given

D₀ = 4.000 cm

α = 1.1 x 10⁻⁵/degrees celsius

we have D = 4 + (4x(1.1 x 10⁻⁵)T = 4 + (4.4x10⁻⁵)T             EQN 1

Similarly for the Aluminium ring we have

we were given

d₀ = 3.994 cm

α = 2.4 x 10⁻⁵/degrees celsius

we have d = 3.994 + (3.994x(2.4 x 10⁻⁵)T = 3.994 + (9.58x10⁻⁵)T       EQN 2

Since @ the temperature T at which the sphere fall through the ring, d=D

Eqn 1 = Eqn 2

4 + (4.4x10⁻⁵)T =3.994 + (9.58x10⁻⁵)T, collect like terms

0.006=5.18x10⁻⁵T

T=115.7K

4 0
4 years ago
Explain why Earth is not a perfect sphere?
Nesterboy [21]

Answer:

Hi ,

It's caused by force act by earth when it rotates

8 0
3 years ago
If you push on a wall of a building what will happen
mixas84 [53]

Answer: It will push back with an equal amount of force.

8 0
3 years ago
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