Answer:
If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.
Answer:
the third stage was 480 km long
Explanation:
Stage 1:
Time = 1 hours
Speed = 80km
Stage 2:
Time = 2 hours
Speed = 200km
Stage 3:
Time = 4 hours
Let the Distance at the stage 3 be x
Average speed of the train route = 100 km/h
So


Lets find the speed at stage 1
Speed = 
Speed = 
Speed 1= 80 km/hr
The speed at stage 2
Speed = 
Speed = 
Speed 2 = 100 km/hr
The speed at stage 3
Speed = 
Speed = 
Speed 3 = 
we kow that average is ,









x = 480
Answer:
One of the leading theories of hot-Jupiter formation holds that gas giants in distant orbits become hot Jupiters when the gravitational influences from nearby stars or planets drive them into closer orbits. They formed as gas giants beyond the frost line and then migrated inwards.
Explanation:
In the migration hypothesis, a hot Jupiter forms beyond the frost line, from rock, ice, and gases via the core accretion method of planetary formation. The planet then migrates inwards to the star where it eventually forms a stable orbit. The planet may have migrated inward smoothly via type II orbital migration.
Hot-Jupiters are heated gas giant planets that are very close to their stars, just a few million miles distant and orbiting their stellar hosts in just a few days. The reason why there isn't one in our Solar System is down to its formation. All gas giants form far from their star but then some migrate inwards.
Hot-Jupiters will just happen to transit about 10% (that is, since orbital planes) this is consistent with the rate expected from geometry of . The actual frequencies of hot Jupiters around normal stars is surprisingly hard to figure out.
Answer:
The voltage drop through which the proton moves is 39.1 V.
Explanation:
Given that,
Distance = 4.76 cm
Time 
We need to calculate the acceleration
Using equation of motion

Where, s = distance
a = acceleration
t = time
Put the value in the equation



We need to calculate the voltage drop
Using formula of electric field

....(I)
Using newton's second law
....(II)
Put the value of F in equation (I) from equation (II)


Where, q = charge
a = acceleration
d = distance
m= mass of proton
Put the value into the formula


Hence, The voltage drop through which the proton moves is 39.1 V.
Answer:
a) h = 14 m
b) h = 88 cm
c) f = 0.054 Hz
d) f = 0.13 Hz
Explanation:
a) T = 2π√(L/g)
L = T²g/4π²
L = (45/6)²(9.8) / 4π² = 13.963...
b) ½mv² = mgh
h = v²/2g
h = 4.15²/ (2(9.8)) = 0.87869
c) f = 1/T = 1 / (2π√(14 / 1.62)) = 0.0542
d) f = 6/45 = 0.13333...