Proton is a positively charged particle
That is a capital U with the number 238 at upper left of the letter
Answer:
<h3>The answer is 1064.75 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of substance = 250 cm³
density = 4.259 g/cm³
We have
mass = 4.259 × 250
We have the final answer as
<h3>1064.75 g</h3>
Hope this helps you
Answer:
Kₐ = 1.2 × 10⁻⁷
Explanation:
Step 1. Calculate [H₃O⁺]
2. Calculate Kₐ
HNO₂ + H₂O ⇌ H₃O⁺ + NO₂⁻
I/mol·L⁻¹: 0.025 0 0
C/mol·L⁻¹: 0.025-5.4 × 10⁻⁵ +5.4 × 10⁻⁵ +5.4 × 10⁻⁵
E/mol·L⁻¹: 0.025 5.4 × 10⁻⁵ 5.4 × 10⁻⁵
So, at equilibrium,
[H₃O⁺] = [NO₂⁻] = 5.4 × 10⁻⁵ mol·L⁻¹
[HF] = 0.025 mol·L⁻¹
Kₐ = {[H₃O⁺][NO₂⁻]}/[HNO₂
Kₐ = (5.4 × 10⁻⁵ × 5.4 × 10⁻⁵)/0.025
Kₐ = 2.9 × 10⁻⁹/0.025
Kₐ = 1.2 × 10⁻⁷
The acid is not nitrous acid, because the Kₐ of HNO₂ is 7.2 × 10⁻⁴
Answer:
Explanation:
We can use the Ideal Gas Law to calculate the density of the gas.
pV = nRT
n = m/M Substitute for n
pV = (m/M)RT Multiply both sides by M
pVM = mRT Divide both sides by V
pM = (m/V) RT
ρ = m/V Substitute for m/V
pM = ρRT Divide each side by RT
Data:
p = 1.00 bar
M = 49 g/mol
R = 0.083 14 bar·L·K⁻¹mol⁻¹
T = 0 °C = 273.15 K
Calculation:
ρ = (1.00 × 49)/(0.083 14 × 273.15) = 2.2 g/L
The density of the gas is .