All categories

4 years ago

What is 4,678,679 dL in scientific notation

1 answer:

8 0

4.7e^6 is how I would write it. You simply count in from the right side where the decimal is until you reach the point just before the 4.

You might be interested in

Rhhhhhh hhdjasdlk lksdjdklsj askdj

DochEvi [55]

how is this a question

8 0

4 years ago

Read 2 more answers

The human eye contains a molecule called 11-cis-retinal that changes shape when struck with light of sufficient energy. The chan

Oksanka [162]

Answer:

1.21 × 10⁻³⁰ m

Explanation:

1 mol of photons causing the change in the conformation of 11-retinal has an energy of 164 kJ. We can find out the wavelength (λ) associated with this energy (E) using the Planck-Einstein equation.

E = h . c . λ⁻¹

where,

h is the Planck's constant

c is the speed of light

λ = h . c . E⁻¹ = (6.63 × 10⁻³⁴ J × s) × (3.00 × 10⁸ m/s) × (164 × 10³ J)⁻¹ = 1.21 × 10⁻³⁰ m

3 0

3 years ago

What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?

yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5 . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83 . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0

3 years ago

Carbon dioxide gas is collected at 27.0(degrees)C in an evacuated flask with a measured volume of 30.0L. When all the gas has be

White raven [17]

Answer:

Moles of carbon dioxide gas is 0.584 moles.

Mass of 0.584 moles of carbon dioxide gas is 25.7 g

Explanation:

Using ideal gas equation

PV = nRT

where,

P = Pressure of gas = $0.480 atm$

V = Volume of gas = 30.0 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 27°C = 300.15 K

Putting values in above equation, we get:

$(0.480 atm)\times 30.0 L=n\times (0.0821L.atm/mol.K)\times 300.15K\\\\n=0.5844 mol\approx 0.584$

Moles of carbon dioxide gas = 0.584 moles

Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7 g

5 0

3 years ago

He difference between elements and compounds is that...

Katarina [22]

A- elements have only one type of atom but compounds have multiple

4 0

3 years ago

Read 2 more answers