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lesya [120]
3 years ago
14

What is 4,678,679 dL in scientific notation

Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0
4.7e^6 is how I would write it. You simply count in from the right side where the decimal is until you reach the point just before the 4.
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Are these ramen noodles expired?
laiz [17]

Answer:

i think so

Explanation:

just eat them anyways

6 0
3 years ago
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A pure substance is matter that consists of matter with a composition that
sashaice [31]
Is constant (matter that has a composition that is the same everywhere)
7 0
3 years ago
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An aluminum block has a density of 2.70 g/mL. If the mass of the block is 24.60 g, find the volume of the substance.
harina [27]

Volume of a substance can be determined by dividing mass of the substance by its density.

That can be mathematical shown as:

Density=Mass/Volume

So, Volume=Mass/Density

Here mass of the substance given as 24.60 g

Whereas density of the substance is 2.70 g/mL

So,

Volume=Mass/Density

=24.6/2.7

=9.1 mL

So volume of the substance is 9.1 mL.

8 0
3 years ago
A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40
Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = 40 hr/week\times 8 week = 320 hours

The concentration of xylene in the workplace =40 \mu g/m^3

The worker is inhaling air at a rate of 0.9 m^3/hr.

Amount xylene inhaled by worker in an hour :

= 40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr

Amount xylene inhaled by worker in 320 hours:

36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

\frac{24}{320}\times 11.520 mg=0.864 mg

Assuming 70 kg body mass, the chronic daily intake of xylene :

\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0
3 years ago
What is the mass in grams of 2.00 10 5 atoms of naturally occurring neon
lesantik [10]

Answer:

2.00X10^5 x 20gNe/6.02x10^23=6.46x10^-18 but books answer is 797.

Explanation:

3 0
3 years ago
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