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katovenus [111]
3 years ago
9

Chris jogged 1 3 of a mile to his friends house in 1 12 of an hour. Compute the unit rate from the complex fraction 1 3 1 12 mil

es per hour. A) 2 miles per hour B) 3 miles per hour C) 4 miles per hour D) 6 miles per hour

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0

The unit rate from the complex fraction ¹/₃ ÷ ¹/₁₂ is 4 miles per hour

<h3>Further explanation</h3>

Order of Operations in Mathematics follow this following rule :

  1. Parentheses
  2. Exponents
  3. Multiplication and Division
  4. Addition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

<em>Let us tackle the problem!</em>

\texttt{ }

<em>We will calculate the fraction by using this following formula:</em>

\texttt{Speed of Chris} = \texttt{Distance} \div \texttt{Time Taken}

\texttt{Speed of Chris} = \frac{1}{3} \texttt{ miles} \div \frac{1}{12}\texttt{ hour}

\texttt{Speed of Chris} = (\frac{1}{3} \times \frac{12}{1}) \texttt{ miles per hour}

\texttt{Speed of Chris} = (\frac{12}{3}) \texttt{ miles per hour}

\texttt{Speed of Chris} = 4 \texttt{ miles per hour}

\texttt{ }

<h2>Conclusion:</h2>

The unit rate from the complex fraction ¹/₃ ÷ ¹/₁₂ is 4 miles per hour

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Order of Operations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS

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Alexxandr [17]

Answer:

The answer is 4 + 3/6 + 2/6

Step-by-step explanation:

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3 years ago
In triangle RST, m∠R &gt; m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
solmaris [256]

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>
  1. prove the statement starting from known facts, or
  2. disprove the statement by finding a counterexample

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

<u>Option 1.  m∠R > 90°</u>

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

  1. The left side of this inequality is 2*m∠R
  2. The right side of the inequality is exactly equal to the Triangle Sum Theorem expression

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

<u>Option 2.  m∠S + m∠T < 90°</u>

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

  1. The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
  2. The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

<u>Option 3.  m∠S = m∠T</u>

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

<u>Option 4.  m∠R > m∠T</u>

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

<u>Option 5.  m∠R > m∠S</u>

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

<u>Option 6.  m∠S > m∠T</u>

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

4 0
1 year ago
7cm<br>10cm<br>4cm<br>The area of the compound shape is 106cm.<br>work out the size of x.​
uranmaximum [27]

Answer: 9cm

Step-by-step explanation:

7x10=70cmx^{2}

4(x)=4x

1.) 70+4x=106 (subtract 70 on both sides)

2.)4x=36 (divide 4 on both sides)

3.)x=9

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3 years ago
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What's 2|-9| - |-2|?
UNO [17]

Answer:

16

Step-by-step explanation:

First, simplify by finding the absolute values:

2|-9| - |-2|

2(9) - (2)

Then, simplify this by multiplying 2 and 9:

18 - 2

= 16

So, the answer is 16

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2 years ago
What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la
olga55 [171]
Let's say the first number is "a"
the next consecutive can just be "a+1" and  the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2

now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5

thus   a(a + 1) = 5(a + 2) - 5   <----- solve for "a"
7 0
3 years ago
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