The 1st one
Well it's the same as normal exponents so you multiply 2/3 x 2/3 x 2/3 x 2/3 x 2/3
One hundred and twenty thousand
Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
Answer:
I think D
Step-by-step explanation:
Since both values are positive, it is in quadrant 1
