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MissTica
3 years ago
14

Write a balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution. A) Na2S(s) → Na+(aq) + S(s

) B) NaS2(s) → Na+(aq) + 2S2-(aq) C) Na2S(aq) → 2Na+(s) + S2-(s) D) Na2S(s) → 2Na+(aq) + S2-(aq)

Physics
2 answers:
svlad2 [7]3 years ago
6 0

D) Na2S(s) → 2Na+(aq) + S2-(aq)

Alisiya [41]3 years ago
3 0

Answer: D) Na_2S(s)\rightarrow 2Na^+(aq)+S^{2-}(aq)

Explanation: Decomposition reaction is a chemical reaction in which one reactant decomposes to give two or more than two products.

The substances which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Thus when sodium sulfide dissociates in aqueous solution, it gives ions which are present in aqueous form.

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The closest star to our solar system is Alpha Centauri, which is 4.12 × 10^16 m away. How long would it take light from Alpha Ce
bonufazy [111]

Time = (distance) / (speed)

Time = (4.12x10^16 m) / (3 x10^8 m/s)

Time = 1.37 x 10^8 seconds

Divide the seconds by 86,400 to get days. Then divide the days by 365 to get years.

Time = about 4.35 years

4 0
3 years ago
A turntable reaches an angular speed of "45 rev/min" in "4.10 s" after being turned on. What is its angular acceleration?
Marina86 [1]

Answer:

1.15 rad/s²

Explanation:

given,

angular speed of turntable = 45 rpm

                       =45\times \dfrac{2\pi}{60}

                       =4.71\ rad/s

time, t = 4.10 s

initial angular speed = 0 rad/s

angular acceleration.

\alpha = \dfrac{\omega_f-\omega_0}{t}

\alpha = \dfrac{4.71-0}{4.10}

\alpha = 1.15\ rad/s^2

Hence, the angular acceleration of the turntable is 1.15 rad/s²

3 0
3 years ago
a car, which has a mass of 2000kg traveled a distance of 200 meters in 5 seconds. After 20 seconds the car was raveling at a spe
iragen [17]

Answer:

Explanation:

vi = 200/5 = 40 m/s

a = (vf - vi)/t = (60 - 40)/20 = 1 m/s²

F = ma = 2000(1) = 2000 N

4 0
2 years ago
A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 108.7 g of water at 60.2°C with 108
Oduvanchick [21]

Answer : The heat capacity of the calorimeter is, 6.72J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of water = 4.184J/g^oC

c_2 = specific heat of calorimeter = ?

m_1 = mass of water = 108.7 g

m_2 = mass of calorimeter = 108.7 g

T_f = final temperature of mixture = 35.0^oC

T_1 = initial temperature of water = 60.2^oC

T_2 = initial temperature of calorimeter = 19.3^oC

Now put all the given values in the above formula, we get

(108.7g)\times (4.184J/g^oC)\times (35.0-60.2)^oC=-(108.7g)\times c_2\times (35.0-19.3)^oC

c_2=6.72J/g^oC

Therefore, the heat capacity of the calorimeter is, 6.72J/g^oC

3 0
3 years ago
Early in the morning, when the temperature is 4.5 ∘C, gasoline is pumped into a car's 53-L steel gas tank until it is filled to
Lynna [10]

Answer:

\Delta V=1.0911\ L

Explanation:

Given:

  • Initial temperature, T_i=4.5^{\circ}C
  • initial volume, V_i=53\ L
  • final temperature,  T_f=27^{\circ}C
  • volumetric coefficient of thermal expansion for gasoline, \beta_g=950\times 10^{-6}\ K^{-1}
  • volumetric coefficient of thermal expansion for steel, \beta_s=35\times 10^{-6}\ K^{-1}

<u>Now the increment in the volume of the container:</u>

\Delta V_s=V_i.\beta_s.\Delta T

\Delta V_s=53\times 35\times 10^{-6}\times (27-4.5)

\Delta V_s=41737.5\times 10^{-6}\ L

<u>and the increment in the volume of the gasoline:</u>

\Delta V_g=V_i.\beta_g.\Delta T

\Delta V_g=53\times 950\times 10^{-6}\times (27-4.5)

\Delta V_g=1132875\times 10^{-6}\ L

<u>Hence the difference in the increment of the two volumes:</u>

\Delta V=\Delta V_g-\Delta V_s

\Delta V=(1132875-41737.5)\times 10^{-6}

\Delta V=1.0911\ L of the gasoline spills out of the container in this case.

3 0
4 years ago
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