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3 years ago

Please Help test is worth a lot !!!

Physics

1 answer:

swat323 years ago

3 0

Answer:

3.667m/s

Explanation:

Momentum = mass * speed.

Momentum before (A+B) = momentum after (A+B)

$m_{a}u_{a}+m_{b}u_{b}=m_{a}v_{a}+m_{b}v_{b}$

100*4 + 150*0 = 100(-1.5) + 150v $_{b}$

400 = -150 + 150v $_{b}$

150v $_{b}$ = 550

v $_{b}$ =3.667m/s

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A horizontal pipe of diameter 1.03m has a smooth constriction to a section of diameter 0.618 m. The density of oil flowing in th

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Velocity of the oil in the pipe: 0.76 m/s, in the constricted section: 5.87 m/s

Explanation:

We can solve this problem by using Bernoulli's equation:

$p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho v_2^2$ (1)

where

$p_1 = 7340 N/m^2$ is the pressure in the pipe

$p_2 = 5505 N/m^2$ is the pressure in the constricted section

$\rho = 821 kg/m^3$ is the density of the oil

$v_1$ is the velocity of the oil in the pipe

$v_2$ is the velocity of the oil in the constricted section

Also, according to the continuity equation,

$A_1 v_1 = A_2 v_2$

where

$A_1 = \pi r_1^2$ is the cross-sectional area of the pipe, with

$r_1 = \frac{1.03}{2}=0.515 m$ is the radius

$A_2 = \pi r_2^2$ is the cross-sectional area of the constricted section, with

$r_2=\frac{0.618}{2}=0.309 m$ is the radius

So the equation becomes

$r_1^2 v_1 = r_2^2 v_2$

So we can write

$v_2=\frac{r_1^2}{r_2^2}v_1$

Substituting into eq.(1),

$p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho (\frac{r_1^2}{r_2^2}v_1)^2$

And solving the equation for $v_1$ :

$p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho \frac{r_1^4}{r_2^4}v_1^2\\v_1=\sqrt{\frac{p_2-p_1}{\frac{1}{2}\rho-\frac{1}{2}\rho \frac{r_1^4}{r_2^4}}}=0.76 m/s$

And the velocity in the constricted section is

$v_2=\frac{r_1^2}{r_2^2}v_1=5.87 m/s$

Learn more about flow rate:

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#LearnwithBrainly

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2 years ago

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3 years ago

How can I become a good science student ?

iris [78.8K]

Answer:

Study hard , focus on your studies and alyways ask questions .

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2 years ago

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1. As you get ready for bed, you roll up one of your socks into a tight ball and toss it into the laundry

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Answer:

When you toss a rolled up sock across the room, it travels faster as it becomes round and has more weight added on it and this causes the sock to travel in the direction you wish and this gives you a high chance of the sock going straight into the laundry basket, no matter how far away you are.

On the other hand, throwing a sock without rolling it up will cause the sock to just flat down as you throw it. It will travel at a low speed because it has no weight on it since it is flat, and if you try to throw it, it will atleast land 21 cm away from you. About a 0% chance of it getting in the basket.

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2 years ago

Is a battery a resistor

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